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Any pair of numbers where the 'y' is 5 more than the 'x'. There are an infinite number of suitable pairs.

2y-2x=10

2y-2x+2x=10+2x

2y=2x+10

divide both side by 2.

y=x+5

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X plus 2y equals 10 and 4y - 20 equals 2x?

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To determine the number of solutions for the system of equations (x + 2y = 10) and (4y - 20 = 2x), we can rewrite the second equation as (2x - 4y + 20 = 0). Rearranging gives us (x = 2y + 10). Substituting this into the first equation leads to a consistent system, indicating that there is exactly one solution where the lines intersect. Thus, the system has one unique solution.


How do you do 4x 2y equals 10 and solve for y?

To solve the equation (4x + 2y = 10) for (y), first isolate (2y) by subtracting (4x) from both sides: (2y = 10 - 4x). Then, divide both sides by 2 to solve for (y): (y = 5 - 2x). Thus, the solution for (y) in terms of (x) is (y = 5 - 2x).


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