Since a^2 + b^2 = 50 and a, b are (nonnegative) integers, you know that neither a nor b can be more than 8 (since 7^2 = 49 is the biggest square that "fits" within the 50-area constraint.
That immediately should show you that a=7, b=1 works. 49 + 1 = 50.
The other one is equally easy: a=5, b=5. 25+25=50.
So (7,1) and (5,5) are the two combinations of side lengths.
If the lengths of the two sides of a right triangle on either side of the 90 degree angle are 150 inches and 200 inches, the length of the hypotenuse is: 250 inches.
Any length greater than 3 inches.
No, because you should be able to add up any two side lengths and their sum should be greater than the third side length. 38 + 29 is not greater than 73.
Pythagoras.
Yes, this is known as the Pythagorean theorem. It states that a2 + b2 = c2 where a and b are the lengths of the two sides on either side of the right angle and c is the length of the hypotenuse.
The 4 sides of a square are of equal lengths
The length of the hypotenuse of a right triangle with legs of lengths 6 and 8 inches is: 10 inches.
They are straight lines. The sum of the squares of the lengths of the two shorter sides is equal to the square of the length of the longest side. But subject to that constraint, the sides can have any lengths.They are straight lines. The sum of the squares of the lengths of the two shorter sides is equal to the square of the length of the longest side. But subject to that constraint, the sides can have any lengths.They are straight lines. The sum of the squares of the lengths of the two shorter sides is equal to the square of the length of the longest side. But subject to that constraint, the sides can have any lengths.They are straight lines. The sum of the squares of the lengths of the two shorter sides is equal to the square of the length of the longest side. But subject to that constraint, the sides can have any lengths.
If two squares have the same side length for all sides, then they are congruent.
Yes
Correct.
length x length = area length = square root of 441= 21 inches
The lengths of each side is 9 inches.
Pythagorean Theorem
how many squares with sides that are 6 inches long are needed to cover a squae with a side length of 30 inches without overlapping
How many squares with sides that are 6 inches long I needed to cover a square with a side length of 30 inches without overlapping
The Pythagorean theorem states that the length of the hypotenuse of a right triangle is the square root of the sum of the squares of the other two sides.[(24 in)^2 + (7 in)^2]^(1/2) = 25 in