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Your daughter is twice as old as your son and half as old as you are In 22 years your son will be half your age So how old is your daughter?
Wiki User
∙ 11y ago
To figure it out we need to set up algebraic equations relating everyone's current age:
x = Brother's age
2x = Sister's age
4x = Parent's age
Which means in 22 years:
x+22 (Brother)= (4x+22)(Parent)/2
Multiply both sides by 2
2x+44 =4x+22
Divide both sides by 2
x+22=2x+11
Subtract 11 from both sides
x+11 = 2x
Subtract x from both sides
11 = x
Mary is now 22 yrs old, her brother is 11, and her parent is 44 yrs old. In 22 years, her brother will be 33 and her parent will be 66, while Mary will be 44 yrs old.
Wiki User
∙ 11y ago
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Mary is now 22 yrs old, her brother is 11, and her father is 44 yrs old. In 22 years, her brother will be 33 and her father will be 66, while Mary will be 44 yrs old. To figure it out we need to set up algebraic equations relating everyone's current age: M (mary's age now) = 2*B (brother's age now) M = 1/2*F(father's age now) In 22 years from now, her brothers age will be half her father's age. So, B+22 = 1/2(F+22) We can use these equations to solve for everyone's age now. (1) Since Mary's age now is twice her brothers and half of her fathers we combine the first two equations to get: 2B = 1/2F or F=4B, so her father's age now is 4 times her brother's age now. (2) Using this equation and substitute the value for F in the equation which relates her brother's and father's ages 22 years from now and solve for her brother's age now. B + 22 = 1/2 (4B + 22) B + 22 = 2B + 11 B = 11, and F = 4*(11) = 44, and M=2*11=22
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