OK, so let's say the length of the base = x. The leg length = 3x, as it's three times the base length. As there are two legs and a base making up the perimeter, the perimeter = 10x. So 62 = 10x. 62/10 = 6.2, therefore x = 6.2 and the base = 6.2 inches.
Hope this helps!
If base = x and each leg = 3x, then the perimeter would be 7x instead of 10x as mentioned above. (3x + 3x +x = 7x). Hence, perimeter = 7x and the base (x) = 8.857 inches.
It depends on the length of the other two sides !
69 meters in length, 19 meters in width makes the perimeter 176 meters.
168.8 cubic inches
31.65 sq'
16.5 x 11.7 in
If the base of an isosceles triangle is 11 and its perimeter is 39, then it has a height of 12.87.
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
Let the base length be x:- If: 2(0.5x+9)+x = 146 => x+18+x = 146 => 2x = 146-18 => x = 64 Therefore the isosceles triangle has 2 equal sides of 41 inches and a base of 64 inches Check: 41+41+64 = 146 inches
Perimeter of the isosceles triangle: 16.2+16.2+8.1 = 40.5 cm
3y - 3
I don't see any isosceles triangle below.In general, the perimeter is the sum of the lengths of all sides. Note that in an isosceles triangle, two of the three sides have the same length.
The perimeter of an equilateral triangle with a side length of 4 inches is 12 inches. Each side of an equilateral triangle is equal in length, so the perimeter is found by multiplying the side length (4 inches) by 3.
Assuming that neither of the sides of equal length is the base, Perimeter = Base + 2*Slanted sides.
12 inches
That's not enough information to solve the problem.
Perimeter = 10 + 10 + 12 = 32 units. Area = 48 square units
2.5 inches