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OK, so let's say the length of the base = x. The leg length = 3x, as it's three times the base length. As there are two legs and a base making up the perimeter, the perimeter = 10x. So 62 = 10x. 62/10 = 6.2, therefore x = 6.2 and the base = 6.2 inches.

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If base = x and each leg = 3x, then the perimeter would be 7x instead of 10x as mentioned above. (3x + 3x +x = 7x). Hence, perimeter = 7x and the base (x) = 8.857 inches.

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Q: When the length of the base of an isosceles triangle is one third the length of one of its legs the perimeter of the triangle is 62 inches what is the length of the base?
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