e^(3lnx)=e^[ln(x^3)]=x^3
e^(ln 3) = 3
e1 + (lnx) = e1 * e(lnx) = e * x = ex
0.8333
There are 2 interpretations of your question: First: e^[lnx + lny] =e^[ln(xy)] =xy Second: lny + e^(lnx) =lny + x
e2xlnx = x2x since ln x is the opposite to e so you just leave the x from the log and the rest of the exponent stays the same.
It depends. If you mean (ln e)7, then the answer is 1, since (ln e) = 1. If you mean ln(e7), then the answer is 7, since ln(e7) = 7 (ln e) and (ln e) = 1.
Cube root is the same as to the power of a third; when multiplying/dividing powers of a number add/subtract the powers; when a power is to another power, multiply the powers; as it is all e to some power: e³/(e²)^(1/3) × e^13 = e³/e^(2/3) × e^13 = e^(3 - 2/3 + 13) = e^(15 1/3) = e^(46/3) Which can also be expressed as "the cube root of (e to the power 46)" or "(the cube root of e) to the power 46".
e times 5 = X
81
1
Think of ln 1 as "e to what power will given me 1." Anything to the zero power will give you 1. So, ln 1 = 0, and 0/2 = 0