P = I ( 1 + y'^2 )^1/2 dx
Where: I - Integral (from point a to point b)
suppose the circle is x^2 +y^2 + a^2
the perimetr will be 4 times the perimeter in the first quadrant
now take a small element
ds on the curve
by Pythagoras theorm
ds2 = dx2 + dy2
now rearange
to get the formula on top
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To find the area you multiply pi (3.14) by the radius and then multiply your answer by the radius again. For example:
Say the radius is 10cm. You would go 3.14x10x10.
IMPORTANT: 3.14xr2
is different than 3.14xrx2!
Also, if you have the circumference of the circle but need the radius, just divide the circumference by 2.
Hope this helps!