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To find the perimeter of polygon efgh, you need the ratio of similarity between polygons abcd and efgh, as well as the perimeter of polygon abcd. Once you have the perimeter of abcd, multiply it by the ratio to obtain the perimeter of efgh. If the ratio is not provided, it cannot be determined.
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Is it true that if a line is parallel to a plane then any plane containing that line is always parallel to the given plane?
No. A line can be contained by many, many planes, Picture this, A rectangle with corners - going clockwise - A, B, C and D is the screen of your computer. This is a plane figure. 1 inch away from it a line runs from A1 to C1. The line is parallel to the plane. Now, take a sheet of paper with corners E, F, G and H, and place corner E at corner A of the screen, and place corner F at corner C of the screen. The Line AI is now 'contained' in the plane EFGH. and EFGH is perpendicular to ABCD.
How can you form six four person teams out of eight players so that in three matches all players will be teamed with everyone in the group at least once?
One possible combination is ABCD v EFGH ABEF v CDGH ABGH v CDEF This has been worked with people staying in pairs. So that at different times AB are partnered with CD, EF and GH and the same applies to the other three pairs. There are many more combinations where constant pairings are not important.
How do you carve a cube to make a square pyramid?
Suppose the top face of the pyramid is ABCD with the square EFGH directly below it.Suppose AC and BD meet at P, the apex of the pyramid.Make a cut with a plane through P which is parallel to AB and goes through EF.Make a cut with a plane through P which is parallel to BC and goes through FG.Make a cut with a plane through P which is parallel to CD and goes through GH.Make a cut with a plane through P which is parallel to DA and goes through HE.The result will be the square-based pyramid PEFGH.
Is it true if a line is parallel to plane it is parallel to any line in the plane?
If your definition of parallel lines is that they never meet, then the answer is yes. If, however, the definition is that they remain equidistant from one another at all points, then, in my opinion, the answer is no. It is difficult to explain the second without recourse to diagrams which are very difficult to manage on this site. So consider a cube with vertices ABCD forming the top face and EFGH (in corresponding order) forming the bottom face. Now AB is parallel to the bottom plane - EFGH. And AB is clearly parallel to EF and any line parallel to EF. But is AB parallel lines such as FG? True, they will never meet but the distance between them increases as you move away from BF - ie they are not the same distance apart. Incidentally, Euclid's parallel postulate was phrased in a very different way from the one most mathematicians come across it. That version is a much later equivalent statement.
How do you find the midpoint of segment gf if the quadrilateral EFGH has coordinates E 2b b F 3b 2b G b 0 and H 0 0?
Each coordinate of the midpoint of a line segment is the average of the correspondingcoordinates of the end points.'x' of the midpoint = average of 'x' of the endpoints'y' of the midpoint = average of 'y' of the endpointsFor segment GF, you only need the coordinates of 'G' and 'F'.G . . . (b, 0)F . . . (3b, 2b)'x' of the midpoint = 1/2 (b + 3b) = 1/2 (4b) = 2b'y' of the midpoint = 1/2 (0 + 2b) = 1/2 (2b) = bCoordinates of the midpoint . . . (2b, b)
