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Solve for x where x is the measure of an angle?
you do x(3.45) and add how ever much u feel is good.dont be mad,get glad!
What is the measure of an angle that is nine times its supplement?
The supplement of an angle x is equal to 180 - x. The measure of an angle that is nine times its supplement can be written as: x = 9(180 - x) You can then solve for the measure of the angle x: x = 1620 - 9x 10x = 1620 x = 162 Therefore, that angle which is nine times its supplement is itself 162 degrees.
If a supplement of an angle has a measure 78 less than the measure of the angle what are the measures of the angles?
Suppose the angle is x then its supplement is 180 - x so 180 - x = x - 78 that is, 258 = 2x or x = 258/2 = 129 <><><><><> Angle + Supplement = 180 Angle = Supplement + 78 Solve for the system of equations... Angle + Supplement = 180 Angle - Supplement = 78 ------------------------------------- 2 Angle = 258 Angle = 129 Supplement = 51
How do you solve if angle x and angle y are complementary and angle z and angle q are complementary and angle x and angle z are congruent then angle y is congruent to angle q?
x and y are complementary so x + y = 90 and so y = 90 - x z and q are complementary so z + q = 90 and so q = 90 - z x = z so 90 - x = 90 - z that is y = q
What would be an equation for the statement five times the complement of an angle less twice the angle's supplement is 40 degreesFind the measure of the supplement?
Suppose the supplement of the angle is x degrees. Then the angle is 180 - x degrees. Therefore the complement of the angle is 90 - (180 - x) degrees = x - 90 degrees. So 5*(x - 90) - 2*x = 40 Solve the above equation for x.
How do you apply double angle formulas for csc sec cot?
write in terms of sin, cos or tan then use the double angle formulae. I.e. cosec(x)=1/sin(x) =1/[2sin(x)cos(x)]
Find the supplementary angle of 148.7?
Supplementary angles add up to 180 degrees. So, if x is the supplementary angle to 148.7 degrees, solve for x: 148.7+x=180 x=180-148.7=31.3 degrees
If the to angles equal 90 degrees and An angle is 40 degrees more than its complement what is the measure of the angle?
You can solve by substituting (x) for the unknown angle and (x + 40) for the angle plus 40 degrees and set the equation as: x + (x + 40) = 90 (then simplify) 2x + 40 = 90 (then isolate the known from unknown by subtracting 40 from each side of the equation) 2x = 50 (divide both sides by 2 to solve for x) x (the unknown angle) = 25 degrees now you can substitute the value of the angles to prove the equation.
The measure of an angle is fourteen times the measure of a complementary angle. What is the measure of each angle?
Let's denote the measure of the angle as x degrees. The complementary angle would then be 90 - x degrees. According to the given information, we have the equation x = 14(90 - x). Solving this equation, we find x = 70 degrees and the complementary angle is 20 degrees.
Integral of cos squared x?
(x+sinxcosx)/2, can do it by parts or by knowing your double angle formulas
An angle's measure is twice its supplement's what is the measure of the two angles?
A supplemental angle "completes" a given angle to make it a straight angle (180 degrees). The supplement of 90 is 90. The supplement of 100 is 80. As long as the two angles add up to 180 they supplement each other. So, you have some angle, x and its supplement, 180-x. The supplement is twice as big as the angle. 180-x = 2*x Solve for x and you're done!
How do you calculate the point on the edge of a circle that corresponds to a degree given the radius of the circle?
public void getPoint(double r, double angle) { //cosine*hypotenuse=adjasent double x = r * Math.cos (Math.toRadians(angle))//in radians; //sine * hypotenuse =opposite double y=r*Math.sin(Math.toRadians(angle))//also in radians; System.out.println("( "+x+", "+y+" )"); }
