lol hahaha
you do x(3.45) and add how ever much u feel is good.dont be mad,get glad!
The supplement of an angle x is equal to 180 - x. The measure of an angle that is nine times its supplement can be written as: x = 9(180 - x) You can then solve for the measure of the angle x: x = 1620 - 9x 10x = 1620 x = 162 Therefore, that angle which is nine times its supplement is itself 162 degrees.
Suppose the angle is x then its supplement is 180 - x so 180 - x = x - 78 that is, 258 = 2x or x = 258/2 = 129 <><><><><> Angle + Supplement = 180 Angle = Supplement + 78 Solve for the system of equations... Angle + Supplement = 180 Angle - Supplement = 78 ------------------------------------- 2 Angle = 258 Angle = 129 Supplement = 51
x and y are complementary so x + y = 90 and so y = 90 - x z and q are complementary so z + q = 90 and so q = 90 - z x = z so 90 - x = 90 - z that is y = q
write in terms of sin, cos or tan then use the double angle formulae. I.e. cosec(x)=1/sin(x) =1/[2sin(x)cos(x)]
Suppose the supplement of the angle is x degrees. Then the angle is 180 - x degrees. Therefore the complement of the angle is 90 - (180 - x) degrees = x - 90 degrees. So 5*(x - 90) - 2*x = 40 Solve the above equation for x.
You can solve by substituting (x) for the unknown angle and (x + 40) for the angle plus 40 degrees and set the equation as: x + (x + 40) = 90 (then simplify) 2x + 40 = 90 (then isolate the known from unknown by subtracting 40 from each side of the equation) 2x = 50 (divide both sides by 2 to solve for x) x (the unknown angle) = 25 degrees now you can substitute the value of the angles to prove the equation.
Supplementary angles add up to 180 degrees. So, if x is the supplementary angle to 148.7 degrees, solve for x: 148.7+x=180 x=180-148.7=31.3 degrees
(x+sinxcosx)/2, can do it by parts or by knowing your double angle formulas
A supplemental angle "completes" a given angle to make it a straight angle (180 degrees). The supplement of 90 is 90. The supplement of 100 is 80. As long as the two angles add up to 180 they supplement each other. So, you have some angle, x and its supplement, 180-x. The supplement is twice as big as the angle. 180-x = 2*x Solve for x and you're done!
public void getPoint(double r, double angle) { //cosine*hypotenuse=adjasent double x = r * Math.cos (Math.toRadians(angle))//in radians; //sine * hypotenuse =opposite double y=r*Math.sin(Math.toRadians(angle))//also in radians; System.out.println("( "+x+", "+y+" )"); }
Let the larger angle be 2x and the smaller angle be x: 2x+x = 93 3x = 93 Divide both sides by 3 to find the value of x: x = 31 Therefore the larger angle is 62 degrees.