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you do x(3.45) and add how ever much u feel is good.dont be mad,get glad!

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Q: Solve for x where x is the measure of an angle?
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If Angle a 8x plus 6 angle b 6x plus 38 solve for x then find the measure of angle b?

The measure of angle b would depend on the sum of the angles a and b which has not been given so therefore a solution is not possible.


If the measure of an angle is three times the measure of its supplement then find the measure of the angle?

x is the angle you're looking for and 3x is the angle that when added to x must total 180 degrees. Therefore the angle is 45degrees (x + 3x = 180)


What is the measure of each exterior angle of nonagon?

If it is a regular nonagon, then you use the following formula: [(s-2) x 180]/s = angle of one interior angle. (s means the number of sides) Then solve: [(s-2) x 180]/s = [(9-2) x 180]/9 = [7 x 180]/9 = 1260/9 = 140. Then, for the exterior angle, subtract 140 from 360. The measure of the exterior angle of a regular nonagon is 220.


If the to angles equal 90 degrees and An angle is 40 degrees more than its complement what is the measure of the angle?

You can solve by substituting (x) for the unknown angle and (x + 40) for the angle plus 40 degrees and set the equation as: x + (x + 40) = 90 (then simplify) 2x + 40 = 90 (then isolate the known from unknown by subtracting 40 from each side of the equation) 2x = 50 (divide both sides by 2 to solve for x) x (the unknown angle) = 25 degrees now you can substitute the value of the angles to prove the equation.


Angles X and Y are supplementary and the measure of angle X is 24 degrees greater then the measure of angle Y What is the angle measure?

Okay. If two angles are supplementary then the sum of the two angles is equal to 180. This can be represented in an algebraic equation: X + Y = 180 Now it says the angle X is 24 degrees greater than Y. That can also be written algebraically: Y + 24 = X Now we can subsititute this value for X into the original equation and solve: (Y + 24) + Y = 180 2Y + 24 = 180 2Y = 156 Y = 78 Now that we know angle Y, we can plug this in to either of our formulas in order to discover angle X: X + (78) = 180 X = 102 There you go, angle X is equal to 102o and angle Y is equal to 78o

Related questions

What is the measure of an angle that is nine times its supplement?

The supplement of an angle x is equal to 180 - x. The measure of an angle that is nine times its supplement can be written as: x = 9(180 - x) You can then solve for the measure of the angle x: x = 1620 - 9x 10x = 1620 x = 162 Therefore, that angle which is nine times its supplement is itself 162 degrees.


If a supplement of an angle has a measure 78 less than the measure of the angle what are the measures of the angles?

Suppose the angle is x then its supplement is 180 - x so 180 - x = x - 78 that is, 258 = 2x or x = 258/2 = 129 <><><><><> Angle + Supplement = 180 Angle = Supplement + 78 Solve for the system of equations... Angle + Supplement = 180 Angle - Supplement = 78 ------------------------------------- 2 Angle = 258 Angle = 129 Supplement = 51


If Angle a 8x plus 6 angle b 6x plus 38 solve for x then find the measure of angle b?

The measure of angle b would depend on the sum of the angles a and b which has not been given so therefore a solution is not possible.


How do you solve for x in a angle in a double angle?

lol hahaha


An angle's measure is twice its supplement's what is the measure of the two angles?

A supplemental angle "completes" a given angle to make it a straight angle (180 degrees). The supplement of 90 is 90. The supplement of 100 is 80. As long as the two angles add up to 180 they supplement each other. So, you have some angle, x and its supplement, 180-x. The supplement is twice as big as the angle. 180-x = 2*x Solve for x and you're done!


If the measure of an angle is three times the measure of its supplement then find the measure of the angle?

x is the angle you're looking for and 3x is the angle that when added to x must total 180 degrees. Therefore the angle is 45degrees (x + 3x = 180)


How do you solve an alternate angle?

Alternate angles have the same measure, so there is nothing to solve!


What would be an equation for the statement five times the complement of an angle less twice the angle's supplement is 40 degreesFind the measure of the supplement?

Suppose the supplement of the angle is x degrees. Then the angle is 180 - x degrees. Therefore the complement of the angle is 90 - (180 - x) degrees = x - 90 degrees. So 5*(x - 90) - 2*x = 40 Solve the above equation for x.


In parallelogram ABCD if angle A equals 5x plus 30 and angle D equals x find angle c?

In parallelogram ABCD, angle A and angle D are adjacent or consecutive angles and are supplementary, meaning the sum of their measures is equal to 180 degrees. Angles A and C are opposite angles and have the same measure. These are some important properties of parallelograms. So to find the measure of angle C, you first have to find the measure of angle A. You can do that with a little algebra. First, set the expressions for the measures of angles A and D equal to 180 and solve for x. Then plug that value for x into the expression for the measure of angle A, which is the same as the measure for angle C. 5x + 30 + x = 180 6x + 30 = 180 6x = 150 x = 25 Therefore, 5x + 30 = 5(25) + 30 = 125 + 30 = 155 The measure of angle C is 155.


The comlpement of an angle is five times the measure of the angle itself find the angle and its complement?

Complementary angles add up to 90 degrees. If one angle is five times the measure of the other, you can express their measurements as 5x and x. The original angle is x degrees and its complement is 5x degrees. Set the sum of the two angles equal to 90 and solve for x. 5x + x = 90 6x = 90 x = 15 The angle is 15 degrees. Its complement is 5(15) = 75 degrees. 75 + 15 = 90.


What is the measure of the smaller of the two supplementary angles if the measure if the measure of one angle is one fourth the measure of the other angle?

The easiest way (for me) to solve this type of question is to put it into an equation in terms of x.Since one angle is 1/4 the size of the other, the two angles would be x and 1/4x, or 4x and x (I suggest using 4x and x).Since the angles are supplementary, their sum is 180 degrees.4x+x=1805x=180x=36 degrees


The measure of the second angle of a triangle is 21 degrees more then the measure of the first angle the measure of the third angle is 15 degrees less than the measure of the first angle. each is?

Let the measure of the first angle be x⁰. So that the second angle would be (x + 21)⁰, and the third one would be (x - 15)⁰.Since the sum of angle measures in a triangle is 180⁰ we have:x + x + 21 + x - 15 = 1803x = 174x = 58Thus, the first angle is 58⁰, the second angle is 79⁰, and the third angle is 43⁰.