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If Angle a 8x plus 6 angle b 6x plus 38 solve for x then find the measure of angle b?
The measure of angle b would depend on the sum of the angles a and b which has not been given so therefore a solution is not possible.
If the measure of an angle is three times the measure of its supplement then find the measure of the angle?
x is the angle you're looking for and 3x is the angle that when added to x must total 180 degrees. Therefore the angle is 45degrees (x + 3x = 180)
What is the measure of each exterior angle of nonagon?
If it is a regular nonagon, then you use the following formula: [(s-2) x 180]/s = angle of one interior angle. (s means the number of sides) Then solve: [(s-2) x 180]/s = [(9-2) x 180]/9 = [7 x 180]/9 = 1260/9 = 140. Then, for the exterior angle, subtract 140 from 360. The measure of the exterior angle of a regular nonagon is 220.
If the to angles equal 90 degrees and An angle is 40 degrees more than its complement what is the measure of the angle?
You can solve by substituting (x) for the unknown angle and (x + 40) for the angle plus 40 degrees and set the equation as: x + (x + 40) = 90 (then simplify) 2x + 40 = 90 (then isolate the known from unknown by subtracting 40 from each side of the equation) 2x = 50 (divide both sides by 2 to solve for x) x (the unknown angle) = 25 degrees now you can substitute the value of the angles to prove the equation.
What is 11 degrees from a angle?
x - 11 degrees, where x is the measure of the angle you started with.
