There are an infinite number of multiples of 3. Five examples may include 3, 6, 9, 12, and 15.
3, 6, 9, 12, 15, 18
The first 5 multiples of 3 are as follows: 3, 6, 9, 12, 15
The multiples of 3 are 3, 6, 9, 12, 15, 18, 21 and so on. The first six multiples of 6 are 6, 12, 18, 24, 30, 36, 42 and so on. Common multiples include all the multiples of 6.
The common multiples of 6 and 9 are the infinite set of multiples of their LCM, which is 18. So the common multiples of 6 and 9 are 18, 36, 54, 72, 90, 108, 126, 144, 162, 180, and so on.
The least common multiples of the number 6 and 9 is 3.
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72
GCF = 3 LCM = 18 Factors of 9: 1, 3, 9 Factors of 6: 1, 2, 3, 6 Multiples of 9: 9, 18 Multiples of 6: 6, 12, 18
Oh, dude, like, totally! If a number is a multiple of 6, it means it can be divided evenly by 6, right? And since 6 is just 3 times 2, any number that's a multiple of 6 is also a multiple of 3. It's like getting two for the price of one, man.
They are all multiples of 3
3 yes, 6 no.
There are an infinite number of multiples of 3. Five examples may include 3, 6, 9, 12, and 15.
It is: 90
3, 6, 9, 12, 15, 18
Well, it depends. Since 9 is a bigger number than 3, logic says that not all multiples of three are all also multiples of 9. However, 9 is a multiple of 3 (3x3=9), therefore if we count up the 3x table, every third number will also be a multiple of 9. Eg: 3,6,9,12,15,18. 6 numbers, two are multiples of 9, 9 and 18.
3, 6, 9
No. For example 9 times 3 is 27 but you cant multiply 6 by any hole number to get 27. Hope it helps. :D