The numbers 3,6 and 9 are all multiples of 3 because 3 can go into all of them evenly.
There are an infinite number of multiples of 3. Five examples may include 3, 6, 9, 12, and 15.
3, 6, 9, 12, 15, 18
The first 5 multiples of 3 are as follows: 3, 6, 9, 12, 15
The common multiples of 6 and 9 are the infinite set of multiples of their LCM, which is 18. So the common multiples of 6 and 9 are 18, 36, 54, 72, 90, 108, 126, 144, 162, 180, and so on.
All multiples of 12 are also multiples of 6 and they all can be written as the sum of nine numbers.
The least common multiples of the number 6 and 9 is 3.
Assuming you mean that you want the number of multiples of each, then for 1-100: number of multiples of 2 = 50 number of multiples of 3 = 33 number of multiples of 4 = 25 number of multiples of 6 = 16 number of multiples of 8 = 12 number of multiples of 9 = 11 Assuming you mean that you want the numbers that are multiples of 2, 3, 4, 6, 8 or 9, then some numbers may be multiples of more than one (for example 12 is a multiple of 2, 3, 4 and 6) and so a straight addition of the number of multiples of each cannot be done: Consider 2, 4 and 8 Every multiple of 4 or 8 is also a multiple of 2, so all the multiples of 4 and 8 are counted by the multiples of 2. Consider 3 and 9 Every multiple of 9 is also a multiple of 3, so all the multiples of 9 are counted by the multiple of 3 Consider 2, 3 and 6. Every multiple of 6 is an even multiple of 3, so are counted in both the multiples of 2 and 3. So the total number of multiples of 2, 3, 4, 6, 8 or 9 is the number of multiples of 2 plus the number of multiples of 3 minus the number of multiples of 6: For 1 to 100, Number of multiples of 2 = 50 Number of multiples of 3 = 33 Number of multiples of 6 = 16 So number of multiples of 2, 3, 4, 6, 8 or 9 in 1-100 is 50+33-16 = 67. Assuming you mean that they are multiples of all of 2, 3, 4, 6, 8 and 9, then they must be multiples of the lowest common multiple of 2, 3, 4, 6 ,8, 9 2 = 21, 3 = 31, 4 = 22, 6 = 2131, 8 = 23, 9 = 32 LCM = highest power of the primes used = 2332 = 72 Thus all numbers that are multiples of 2, 3, 4, 6, 8 and 9 are multiples of 72, which means between 1 and 100 only 1 number is a multiple of all of them, namely 72
Yes, multiples of 3 are also multiples of 6. This is because 6 is a multiple of 3, meaning it can be divided evenly by 3. Therefore, any number that is a multiple of 3 will also be divisible by 6. For example, 3, 6, 9, 12, etc., are all multiples of both 3 and 6.
GCF = 3 LCM = 18 Factors of 9: 1, 3, 9 Factors of 6: 1, 2, 3, 6 Multiples of 9: 9, 18 Multiples of 6: 6, 12, 18
They are all multiples of 3
3 yes, 6 no.
There are an infinite number of multiples of 3. Five examples may include 3, 6, 9, 12, and 15.
3, 6, 9, 12, 15, 18
It is: 90
Well, it depends. Since 9 is a bigger number than 3, logic says that not all multiples of three are all also multiples of 9. However, 9 is a multiple of 3 (3x3=9), therefore if we count up the 3x table, every third number will also be a multiple of 9. Eg: 3,6,9,12,15,18. 6 numbers, two are multiples of 9, 9 and 18.
3, 6, 9
No. For example 9 times 3 is 27 but you cant multiply 6 by any hole number to get 27. Hope it helps. :D