997. To test that 997 is prime, we only need to test values up [997^.5], so up to 31. Using divisibility rules, we can immediately eliminate several possible divisors. Rule for 7: If you have a number, separate the last digit from the proceeding ones. Subtract twice the last digit from the number created from slicing off the last part. if that's divisible by seven, the whole number is. For example, take 343. 34-2(3) is 28, which is divisible by 7, so 343 is divisible by 7 Rule for 3: sum of digits is divisible by 3. Rule for 2: last digit is divisible by 2. Rule for 2^n: last n digits form a number that is divisible by 2^n Rule for 5: last digit is 5 or 0. Rule for 11: Difference of alternating sums of the digits, 432113 is divisible by 11 because (4+2+1)-(3+1+3) is divisible by eleven. Rule for 9: sum of digits is divisible by 9. Trying 13, 17, 19, 23, and 29, we see these all fail. So 997 is indeed prime.
203 / 297 = 0.6835 = 68.35% or (taking into account the rule of significant figures) 68.4%
To determine if 42 is divisible by 3, you can add up the digits of 42 (4 + 2 = 6) and check if the sum is divisible by 3. Since 6 is divisible by 3, then 42 is also divisible by 3. This is based on the rule that a number is divisible by 3 if the sum of its digits is divisible by 3.
4, 8, 12, 16, 20, 24, 28, 32, and 36 are the first 9 multiples of 4.
You line the numbers up, one below the other, so that the decimal points are in the same column. You compare the digits in the leftmost column. If one of the digits is large than the other, then that number is bigger. If they are the same, then you move to the next column on the right and repeat the comparisons.There is, however, one exception to this rule. If any number ends with a recurring 9, that decimal number must be rounded (up) to the last digit before the 9s start. That is 3.564999... recurring should be written as 3.565 for the comparisons. This does not apply to any other digit that might recur.
The final answer should have three significant figures as dictated by the measurements provided (10.04 grams and 8.21 cubic centimeters). The result of the calculation cannot have more significant figures than the least precise measurement.
17.0303
There are five significant figures in the given value. It is according to the rule of significant figures which say that zeros right to the decimal point are significant and all non zero digits are significant So , all the digits in the given value are significant figures i.e 5 significant figures.
Add the digits together and if the result is divisible by 9, the original number is divisible by 9.
The significant figures are the first four non-zero digits - with the last of these adjusted if the following digit is 5 or more. [This is the crude school rule rather than the bias-free, IEEE approved rule.] So the answer is 2231000.
3 significant figures.The rule is that the number of digits in your answer should not exceed the lowest number of digits of all the values used to derive the answer.
In math, a significant figure is a digit that carries meaningful information about the precision of a measurement. It includes all the certain digits plus one uncertain or estimated digit. Significant figures help indicate the accuracy or precision of a number or calculation.
Sum the digits in blocks of three from right to left. If the result is divisible by 27, then the number is divisible by 27
Delete any leading zeros.If the number is an integer, delete any trailing zeros.Skip to rule 4.Skip to rule 5.Count the number of digits remaining.
The first rule is to count all the digits from the beginning of the number until the first uncertain digit. The second rule is to round the final answer to match the least precise measurement used in the calculation.
Just do the division and see if there is a remainder (or a decimal). Or use the divisibility rule for three (add the digits, and see if the result is divisible by 3).
When adding or subtracting numbers, the result should have the same number of decimal places as the least number of decimal places in the original numbers. This is because in these operations, you are limited by the least precise measurement. Significance figures don't matter in addition or subtraction, only decimal places.