78 is not prime. No even number (except 2) is prime. Remember the definition. A prime number is exactly divisible only by itself and 1.
How about: 73+5 = 78
78 6 x 13 (2x3) x 13 Since 2, 3, and 13 are prime numbers, the factor tree is complete.
One way to solve this is to multiply the lowest prime numbers together, starting from 2: 2x3=6. 6x5=30. Multiplying by 7 would yield a 3-digit number, so we are looking for all 2-digit numbers with 3 distinct prime factors. We already have 30. 2x3x7=42. 2x3x11=66. 2x3x13=78. 2x5x7=70. So, to answer the original question, the 2-digit numbers that have the most factors in their prime factorization are, in ascending order, 30, 42, 66, 70, and 78.
47 is a prime number.
2, 3 and 13
2 x 3 x 13 = 78
78
78 = 13 x 3 x 2 Therefore, the greatest prime factor of 78 is 13.
No. Numbers that are relatively prime, only have the number 1 as a common factor. 13 and 78 have 1 and 13 as common factors, so they are not relatively prime.
No, 39 isn't prime.
78 39,2 13,3,2
For a number to be divisible by 6, it has to be divisible by 2 and 3, because 2*3=6.In other words, we could divide the number we're factorising (78) by the prime factors of the number we're testing (6, which is 2*3). We start by dividing by 2, because we know 78 is even: 78/2=39. Then, we divide the new number by the other prime factor - 3. 39/3=13 13 is a whole number with no remainders, therefore we can say that 78 is divisible by 6, and therefore 6 is a factor of 78. (6*13=78)
76 7 82 199 02 and 5
The prime factorization of 78 is 2x3x13.
The GCF of 17 & 78 is... 1 - because 17 is a prime number, only divisible by 1 and itself - and 17 is not a factor of 78.
a two digit number is a number that has to digits for example 34 or 78