Assuming x is your number, x * 10^n = x moved n decimal places. When n is positive, move the decimal point n places to the right. When n is negative, move the decimal point n places to the left. When n is 0, do nothing.
8.562 Inspect the 3rd decimal place . In this case it is '2'. The rule is for 'n' decimal places , inspect the 'n+1' decimal place. If the 'n+1' decimal place is between 0 & 4 , then leave the 2nd decimal unchanged. If it is between 5 & 9 then add '1' to the second decimal place. Since in this case the third decimaal is '2' ( between 0 & 4), then leave the 2nd decimal place unchanged. at '6'. Hence 8.452 to 2 d.p. is 8.56 .
If a number called 'N' is greater than 20, you would write N > 20 You can see how the symbol tapers down as it goes from 'N' to 20, because 'N' is bigger and 20 is smaller.
7.5 percent is equivalent to 75/1000 or 3/40 in fraction or 0.075 in decimal
0.2
For simplicity I will assume you're working in base x, for any integer x greater than 1, although the argument extends to integers greater than 1 in absolute value (note that in base -1,1 all decimal numbers are in fact integers and that in base 0 decimals are not very well defined). In base x, x can of course be conveniently denoted as 10, so in the remainder of this answer I will work in base x. It is sufficient to show that there exists a decimal number that is not an integer so take 0.1 or 10^-1. This number has the property that 10*0.1 = 1, it is the multiplicative inverse of 10. I will now prove by induction that no positive integer has this property. Base case: 1*10 = 10 which is greater than 1 by assumption. Suppose n*10 is greater than 1, then (n+1)*10 = n*10+1*10 = n*10 + 10 which is still greater than 1. So we now know that n*10 is always greater than 1 for any n greater than 0, from which it can be deduced that for these n, n*10 is also unequal to -1. Therefore, for no integer n unequal to zero can n*10 be 1. Now assume n=0, then n*10 = 0*10 = 0 which is not equal to 1 either. Thus, no integer n has the property n*10=1, whereas the decimal number 0.1 does. So 0.1 is not an integer and therefore the decimal numbers are not integers.
1
34 654
Assuming x is your number, x * 10^n = x moved n decimal places. When n is positive, move the decimal point n places to the right. When n is negative, move the decimal point n places to the left. When n is 0, do nothing.
This is impossible. A two digit number n divided by 345 has a remainder equal to n. If you meant to say divided by 3,4,5 or 6 then the answer is 62.
l is greater than n
include <iostream> using namespace std; int main() { int n; // number to convert to binary while (cin >> n) { if (n > 0) { cout << n << " (decimal) = "; while (n > 0) { cout << n%2; n = n/2; } cout << " (binary) in reverse order" << endl; } else { cout << "Please enter a number greater than zero." << endl; } } return 0; }//end main
No, for any number n greater than zero, the LCM of n and n is n.
The decimal form of a fraction is either a terminating or recurring decimal.
N/40 = N*0.025
If you're looking for 220 percent of some number n n * 2.2 = 220 percent of n n * x.yz = xyz percent of n In other words, just shift the decimal 2 places to the left for any problem like this.
n + 4 =====