If you are in the mathematics field then you might be using it everyday; otherwise... not so much
This is a difference of two square, so you can apply the factoring rule for the difference of two squares.
There is no general conversion, since they measure different things (volume versus mass). You need to know the density of a specific material to do the conversion for that material, and apply the formula: mass = volume x density
Apply the formula of percent increase,which is : new value - old value / old value so, your question is what percent increase is 12 to 18, here 18 is the new value and 12 is the old value, now apply to the formula: percent increase= 18-12 / 12 = 0.5 now to get the percent multiply by 100 , 0.5*100 = 50% So, the percent increase 12 to 18 is 50%.
To calculate a mathematical formula in Java, you can use standard arithmetic operators like +, -, *, and / for basic calculations. For more complex calculations, you can utilize the Math class, which offers methods for functions like Math.pow(), Math.sqrt(), and Math.sin(). Simply define your variables, apply the necessary operations, and print or return the result. For example: double result = Math.pow(2, 3) + Math.sqrt(16); // Calculates 2^3 + √16 System.out.println(result); // Outputs 10.0
To calculate income tax, one should sum up the totals of all the taxable income and subtract from it the personal allowance and any other tax free allowances. After that, one should apply the rate of tax on the resultant value to find out the income tax payable.
Yes, simply treat the middle coefficient as 0.
The mathematical principles applied to each Quadratic Equation in Standard Form include factorization or factoring, variation(correlation of variables), monomial rules, domain and range.
-2x2 + 9x - 12 = 0Then apply the quadratic formula.
To solve a binomial expression, you typically simplify or factor it. If you're solving an equation set to zero, you can use methods like factoring, completing the square, or applying the quadratic formula if it's a quadratic binomial. For binomials, you may also apply the difference of squares or the sum/difference of cubes formulas if applicable. Always ensure to check your solutions by substituting them back into the original expression.
You will apply them when solving quadratic equations in which the quadratic expression cannot be factorised.
I suggest you apply the quadratic formula (a = 2, b = -4, c = -1).
You can combine equivalent terms. You should strive to put the equation in the form ax2 + bx + c = 0. Once it is in this standard form, you can apply the quadratic formula, or some other method, to solve it.
Find one factor by substituting in values, then use long division. You can then apply the quadratic formula to the result - or factorise it by sight, of course
To answer a physics question using the quadratic formula, first identify the equation that represents the problem. If the equation is in the form of ax^2 + bx + c = 0, you can apply the quadratic formula: x = [-b ± sqrt(b^2 - 4ac)] / 2a. Solve for x using this formula to find the solutions to the equation, which may represent physical quantities such as time, distance, or velocity.
Factoring rates apply to the practice of businesses selling receivables at a discount to a factor, who then collects the funds. The factoring rate is the amount of the discount at which the receivable is purchased.
The usual rules for "order of operation" apply. Don't forget that the square root of a negative number is an imaginary number. As an example, the square root of -9 is 3i (that is, the square root of +9, times the "imaginary unit").
Assuming that "x2" means x squared (x^2): x^2 - 4x - 32 = 0 factoring* (x-8)(x+4) = 0 So the roots are 8 and -4. Sorry I'm not sure what you mean by "symbolic answer." *If you don't see how to factor this trinomial, you can still apply the quadratic formula to get the same answer without being "clever."