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I suggest you apply the quadratic formula (a = 2, b = -4, c = -1).
What else can I help you with?
What are the roots of the quadratic equation x2 - 4x plus 4 equals 0?
x2-4x+4 = 0 (x-2)(x-2) = 0 x = 2 or x = 2 It has two equal roots.
Explain why x2 plus 4x plus 4 equals 0 has 2 x intercepts?
x2+4x+4 = 0 (x+2)(x+2) = 0 x = -2 and also x = -2 When the solutions to a quadratic equation are identical this means that both values are at the turning point or vertex of the parabola just on the x axis. d>=0,then roots of quadratic equation are real if D<0,then roots are imaginary
What are the coordinates of the roots of x2 plus 4x equals 0?
x2 + 4x = 0 ⇒ x(x + 4) = 0 ⇒ x = 0 or x = -4
What is x in the equation 4x 8-20?
To solve the equation (4x + 8 - 20 = 0), first simplify it: (4x - 12 = 0). Then, add 12 to both sides to get (4x = 12). Finally, divide by 4 to find (x = 3).
What are coordinates for -4x plus 9y equals 0?
-4x + 9y = 0 is the equation of a line in the Cartesian plane and the coordinates of any of the infinite number of points on that line will satisfy the equation.
What is the roots of the equation 2xsquare-3x-4 equals 0?
2x2 -3x - 4 = 0 use the qudratic equation and your answers are 1.137458609 and -2.637458609
What is the product of the roots of the equation 2xsquare-x-2 equals 0?
The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.
What is the number and type of roots of the equation x2-4x-32 equals 0?
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
What are the roots of the quadratic equation x2 - 4x plus 4 equals 0?
x2-4x+4 = 0 (x-2)(x-2) = 0 x = 2 or x = 2 It has two equal roots.
What is the sum of the roots x2 - 4x - 5 0?
Their sum is 4.
Explain why x2 plus 4x plus 4 equals 0 has 2 x intercepts?
x2+4x+4 = 0 (x+2)(x+2) = 0 x = -2 and also x = -2 When the solutions to a quadratic equation are identical this means that both values are at the turning point or vertex of the parabola just on the x axis. d>=0,then roots of quadratic equation are real if D<0,then roots are imaginary
What is the quadratic equation with the solutions -1 an 5?
The equation must have roots of x = -1 and x = 5 So: x + 1 = 0 and x - 5 = 0 Therefore: (x + 1)(x - 5) = 0 Expanding the brackets gives the equation: x2 - 4x - 5 = 0
What are the coordinates of the roots of x2 plus 4x equals 0?
x2 + 4x = 0 ⇒ x(x + 4) = 0 ⇒ x = 0 or x = -4
What are the roots of the quadratic equation x squared - 4x -5 equals 0 are?
x2 - 4x - 5 = zero( x - 5 ) ( x + 1 ) = zerox - 5 = zero ...... X = 5x + 1 = Zero ...... X = -1
Which equation has the solution set 1 and 3?
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
What are coordinates for -4x plus 9y equals 0?
-4x + 9y = 0 is the equation of a line in the Cartesian plane and the coordinates of any of the infinite number of points on that line will satisfy the equation.
4x plus y-6 equals 0?
Then the straight line equation is: y = -4x+6
