If m, n, and p are three consecutive integers, then one of them must be even. Let's say the even number is m. Since m is even, it is divisible by two, and so can be written as 2*k, where k is some integer.
This means that
m*n*p = 2*k*n*p.
Since we are multiplying the quantity k*n*p by 2, it must be divisible by two, and therefore must be even.
No. There is no set of three consecutive even integers with a sum of 40.
201
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.
The consecutive odd integers for 114 are 37, 38 and 39.
They are -12, -10 and -8.
Three even integers.Three even integers.Three even integers.Three even integers.
The three integers are 25, 26, and 27.
There is no solution. The sum of multiple even integers will always be even, and -7 is odd.
No. There is no set of three consecutive even integers with a sum of 40.
The even integers are 22, 24 and 26.
Find three consecutive positive even integers whose sum is 123 , Answer
The integers are -30, -28 and -26.
The integers are -16 and -14.
The integers are -14, -12 and -10.
16+18+20= 54
The integers are 44, 46 and 48.
12 + 14 + 16 = 42