11b which is 1*2 + 1*1 = 3 would be for two bits. But a byte is 8 bits, so 2 bytes is 16 bits. The largest binary number is [2^16 - 1], which is 65535 (base ten)
Oh, dude, the BCD number system is like that old-school friend who still uses a flip phone. The advantage is it's easy for humans to read since each decimal digit is represented by a 4-bit binary number. But the downside is it's not very efficient in terms of storage space compared to other number systems. So, like, it's great for nostalgia but not so much for modern computing efficiency.
A byte is 8 binary bits, each of which hold a value of 0 or 1 (true or false). When counting in binary, a value of 11111111 is the highest value a byte can hold, this is 255. It doesn't matter what programming language is assigning a value to the byte, the highest it can hold is 255. A 'signed' byte uses one bit for the sign, and 7 for the value. Hence 7 bits can show values of up to 128 either side. That's a positive value of 1-127, along with the 0, and then negative values of -1 to -128. Again, regardless of the system assigning the value, 8 bits can only produce 255 different combinations.
A byte represented of 8 bits
1 byte = 8 bits
This has a very simples solution. You have to treat the integer part separately from the decimal part. Therefore, you simply convert the integer part (10) to binary, which becomes 1010. Let's work with the decimal part of the number (0.5): We get the decimal part and multiply it by our number system base, which is 2, the amount of times correspondent to our desire of decimal places for the number. 0.5 x 2 = 1.0 Since we only want one decimal place, we stop right now. We obtained the number 1.0, which is the same as 1, the number for the decimal binary. 10.5 = 1010.1 in binary. In byte representation: 1010.1000
The biggest number that can be represented in one byte is 11111111. Binary numbers have the ability to added together in a fashion similar to decimal numbers.
The standard written format for an IP address is as 4 bytes written as their decimal values separated by periods. Just convert each decimal value to a binary byte and append them to make a 32 bit number. Reverse that to convert a 32 bit number to 4 decimal bytes separated by periods.
BCD (binary coded decimal) - 4 bit Byte - 8 bit Byte
Oh, dude, you're asking about binary now? Alright, so in binary, the decimal number 255 is represented as 11111111. It's like all those ones are just hanging out together, having a binary party. So yeah, 255 in binary is just a bunch of ones chilling together.
C# EXAMPLEString text="My sample data";System.Text.ASCIIEncoding encode=new System.Text.ASCIIEncoding();//convert to binary and store in a byte[]byte[] binaryArray=encode.GetBytes(text);
The address of the last byte in a 512 mega byte memory, expressed as a decimal number, is 536,870,911.
The true answer is yes and no Yes: in binary coded decimal and hexadecimal each byte is 4 bits long; in octal each byte is three bits long. No: in true binary theoretically there is no "last bit".
100, 104.858, or 95.367, depending on if you mean decimal to decimal, binary to binary, decimal to binary, or binary to decimal. Simply, decimal megabytes, used by the storage industry, is 1,000KB, where each KB is 1,000 bytes. Binary megabytes, used by programmers (such as Microsoft, Linux, etc) are 1,024 KB, where each KB is 1,024 bytes (2^10, or 0x0200). Converting from decimal to binary will yield a smaller number of megabytes, while converting from binary to decimal will result in more megabytes.
(01110111)2 = hexadecimal byte 77 = (119)10
Class B includes anything that starts with binary "10", or in decimal, 128-191 for the first byte.Class B includes anything that starts with binary "10", or in decimal, 128-191 for the first byte.Class B includes anything that starts with binary "10", or in decimal, 128-191 for the first byte.Class B includes anything that starts with binary "10", or in decimal, 128-191 for the first byte.
Nobody knows what you are talking about, but if you mean what the biggest number is in a byte, it is 255 or 127. The former is only for unsigned, while the latter is the maximun if the byte is signed. If you mean how many numbers can be represented, it is 256 or 128. Again, the former is if it is unsigned and the latter is if it is signed.