96 = 2 x 2 x 2 x 2 x 2 x 3
or in index form
96 = 25 x 3
The answers are 25*3
96 = 2x2x2x2x2x3
96 = 24 × 4=6x4x4=2x3x2x2x2x2
96 = 2 x 2 x 2 x 2 x 2 x 3
2 x 2 x 2 x 2 x 2 x 3 = 96
2 x 2 x 2 x 2 x 2 x 3 or 25 x 3 = 96
96 = 25 x 31
96 = 2x2x2x2x2x3
96 = 25*3
As a product of its prime factors in exponents: 25*3 = 96
96 = 24 × 4=6x4x4=2x3x2x2x2x2
As a product of its prime factors: 2*2*2*2*2*3 = 96
2 x 2 x 2 x 3 x 3 = 72 2 x 2 x 2 x 2 x 2 x 3 = 96
96 = 2 x 2 x 2 x 2 x 2 x 3
2 x 2 x 2 x 2 x 2 x 3 = 96
This Question needs to be answered in a few steps. The first step is to split each number into a product of its prime factors. 64 as a product of its prime factors = 2^6 96 as a product of its prime factors = 2^5*3 The LCM will be written as a product of the largest instances of the indices in each unit above. LCM = 2^6*3 = 192 This should be correct, but it is always good to check. 192/64 = 3; 192/96 = 2, so this answer is plausible. It is: 192
To find the HCF of two numbers you first need to write them as the product of their prime factors: 52 = 2x2x13 96 = 2x2x2x2x2x3 The next step is to identify any common prime factors. In this case, both numbers have two 2s as prime factors. Multiply these and you get: 2x2 = 4 Thus the HCF of 52 and 96 is 4.
The answer is the number of factors of 96 which are :- 96, 48, 32, 24, 16, 12, 8, 6, 4, 3, 2 and 1......making a total of 12 numbers. NOTE : There is a method from Number Theory for determining the number of factors. Express the number in terms of its Prime Factors. 96 = 25 x 31. Then the number of factors is, (5 + 1)(1 + 1) = 6 x 2 = 12. That is, take the exponent of each prime factor, add one to each exponent and take the product. This number provides the number of factors. ,