There is a formula for the "difference of squares." In this case, the answer is (3A + B)(3A - B)
(3a - 5b)(9a2 + 15ab + 25b2)
9a4-b2=36a-2b=2(18-b) But if you meant 9a^4-b^2 it is not possible to factor
The GCF is a2b.
4(16a4 + b2)
There is a formula for the "difference of squares." In this case, the answer is (3A + B)(3A - B)
(3a - 4)(3a - 4)
(3a - 5b)(9a2 + 15ab + 25b2)
a(a^2 - 9a + 3)
The GCF is 3a
9a2 equal 24a minus 16
9a^2 + 42at + 49t^2 = (3a + 7t)(3a + 7t)
a2-b2 = (a-b)(a+b)
9a2=24a-16 9a2-24a+16=0 (3a-4)(3a-4)=0 3a-4=0 a=4/3 double root
9a4-b2=36a-2b=2(18-b) But if you meant 9a^4-b^2 it is not possible to factor
(p-3q) (p-3q) =p2+3pq+3pq+9q2 =p2+6pq+9a2 this is answer hehehhe (jhaylotte)
(a + b)(a - b)