(3a - 4)(3a - 4)
(3a + b)(3a - b)
(3a - 5b)(9a2 + 15ab + 25b2)
a(a^2 - 9a + 3)
I'll assume the missing signs are pluses. 7a^2 - 12a + 14
There is a formula for the "difference of squares." In this case, the answer is (3A + B)(3A - B)
9a2 equal 24a minus 16
9a^2 + 42at + 49t^2 = (3a + 7t)(3a + 7t)
9a2=24a-16 9a2-24a+16=0 (3a-4)(3a-4)=0 3a-4=0 a=4/3 double root
(p-3q) (p-3q) =p2+3pq+3pq+9q2 =p2+6pq+9a2 this is answer hehehhe (jhaylotte)
9and anumber and 2
If that's 9a2, the answer is a(a2 - 9a + 3) x(5x2 + 3x - 1) -8d(d2 + 3d + 1)