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The expression a^3 + b^3 can be factored using the sum of cubes formula, which states that a^3 + b^3 = (a + b)(a^2 - ab + b^2). Therefore, a^3 + b^3 can be factored as (a + b)(a^2 - ab + b^2). This formula helps us break down the sum of two cubes into a product of binomials, simplifying the expression.
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How do you factor x cubed plus 36 x?
x(x2 + 36)
Can you factor the binomial below y cubed plus 27z cubed?
(y + 3z)(y^2 - 3yz + 9z^2)
Factor 2x cubed plus 2x squared - 12x?
2x(x^2+x-6)
What is the greatest common factor of 8c cubed and 24c cubed?
8c cubed
How do you factor the expression x cubed plus 216?
Use a^3 + b^3 = (a + b)(a^2 - ab + b^2), where a^2 is a squared, a^3 is a cubed. Note that 216 = 6^3.
How do you factor a cubed plus a?
a(a^2 + 1)
How do you factor 8xA cubed plus C cubed?
(2a + c)(4a2 - 2ac + c2)
How do you factor x cubed plus 3xsquaredy plus 3xy squared plus y cubed?
(x + y)(x + y)(x + y)
How do you factor x cubed plus 125?
w3+125
How do you factor y cubed plus 27z cubed?
(y + 27)(y^2 - 27y + 729)
How do you factor x cubed plus 36 x?
x(x2 + 36)
How do you factor x plus x cubed?
x(x^2 + 1)
Factor x cubed plus 5x squared plus 6x?
x(x2+5x+6)
Factor sin cubed plus cos cubed?
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
How do you factor x cubed plus 9x squared plus 2x plus 18?
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
Can you factor the binomial below y cubed plus 27z cubed?
(y + 3z)(y^2 - 3yz + 9z^2)
Factor 8x cubed plus 2x squared plus 12x plus 3?
The answer is (2x^2+3)(4x+1)
