x(x2 + 36)
(y + 3z)(y^2 - 3yz + 9z^2)
2x(x^2+x-6)
8c cubed
Use a^3 + b^3 = (a + b)(a^2 - ab + b^2), where a^2 is a squared, a^3 is a cubed. Note that 216 = 6^3.
a(a^2 + 1)
(2a + c)(4a2 - 2ac + c2)
(x + y)(x + y)(x + y)
w3+125
(y + 27)(y^2 - 27y + 729)
x(x2 + 36)
x(x^2 + 1)
x(x2+5x+6)
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
(y + 3z)(y^2 - 3yz + 9z^2)
The answer is (2x^2+3)(4x+1)