w3+125
(x + 3)(x^2 - 3x + 9)
x3 + x = x(x2+1)
2(x^2 + 2)(x + 3)
125 = 5 x 5 x 5... or 125 = 5 cubed.
x3 + 1 = (x + 1)(x2 - x + 1) The x + 1's cancel out, leaving x2 - x + 1
(2x + 5)(4x^2 - 10x + 25)
(x + y)(x + y)(x + y)
x(x^2 + 1)
(x - 5)(x^2 + 5x + 25)
x(x2 + 36)
Factor out the GCF and get X(X2-X+1).
x(x + 9)(x + 1)
x(x + 9)(x + 1)
x3 + 125 Use the sum of two cubes. (x+5)(x2-5x+25)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
x^3 + y^3 = (x + y)(x^2 - xy + y^2)
(x + 3)(x^2 - 3x + 9)