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5(n2 + 2n + 4)

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Q: Factor this Trinomial 5n2 plus 10n plus 20?
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Related questions

Can you factor 5n2 plus 36n plus 7?

(5n + 1)(n + 7)


How do you factor 5n2 10n 20?

Take 5 out. If the missing signs are pluses, it becomes 5(n2 + 2n + 4) If the missing signs are minuses, it becomes 5(n2 - 2n - 4)


What is 5nsq. plus 17n plus 6?

5n2 + 17n + 6 is a quadratic expression. It can be factorised as 5n2 + 17n + 6 = (5n + 2)(n + 3). The expression can be expressed as equal to to a fixed or variable amount when it becomes a function of n. Example : 5n2 + 17n + 6 = 7 or y = 5n2 + 17n + 6


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What is the square roots of -10-5n2-330?

√(-10 - 5n2 - 330) = i√(5n2 + 340) = i√[(5(n2 + 68)]


How do you write the product of the square of a number and five in an formula?

5 * * * * * No. It should be 5n2


What is five n squared plus two n plus six equals zero?

5n2 + 2n + 6 = 0 is a quadratic equation in the variable n.The equation does not have any real roots. The roots are the complex conjugate pair -0.2 ± 1.077i where i is the imaginary square root of -1.


How many grams of NO are required to produce 145g of N2 in the following reaction 4nh3 plus 6no 5n2 plus 6h20?

4NH3 + 6NO -> 5N2 + 6H2O 145 g N2 x (1 mol/28.0 g) x (6 mol NO/5 mol N2) x (30.0 g NO/1 mol NO) = 186.4285714 g NO rounds to 186 g NO due to significant figures


What number comes next 1 2 5 16 41?

86. Generated by the cubic t(n) = n3 - 5n2 + 9n - 4 for n = 1, 2, 3, ...


How many possible mole ratios are there in the equation 4NH3 plus 6NO yields 5N2 plus 6H2O?

There are two possible mole ratios in the balanced equation: 4 moles of NH3 to 6 moles of NO, and 5 moles of N2 to 6 moles of H2O.


What is the reaction equation of the oxidation of acetylene with nitrous oxide?

The reaction equation for the oxidation of acetylene (C2H2) with nitrous oxide (N2O) is: 2C2H2 + N2O -> 2CO2 + H2O + N2


What is the next sequence number 56 50 54?

There are infinitely many rules that can generate this sequence. As imple one is Un = 5n2 - 21n +72 for n = 1, 2, 3, ... And then n = 4 gives U4 = 68