(5n + 1)(n + 7)
Take 5 out. If the missing signs are pluses, it becomes 5(n2 + 2n + 4) If the missing signs are minuses, it becomes 5(n2 - 2n - 4)
5n2 + 17n + 6 is a quadratic expression. It can be factorised as 5n2 + 17n + 6 = (5n + 2)(n + 3). The expression can be expressed as equal to to a fixed or variable amount when it becomes a function of n. Example : 5n2 + 17n + 6 = 7 or y = 5n2 + 17n + 6
-4n3 + 8n2 - 4n + 7
√(-10 - 5n2 - 330) = i√(5n2 + 340) = i√[(5(n2 + 68)]
5 * * * * * No. It should be 5n2
5n2 + 2n + 6 = 0 is a quadratic equation in the variable n.The equation does not have any real roots. The roots are the complex conjugate pair -0.2 ± 1.077i where i is the imaginary square root of -1.
4NH3 + 6NO -> 5N2 + 6H2O 145 g N2 x (1 mol/28.0 g) x (6 mol NO/5 mol N2) x (30.0 g NO/1 mol NO) = 186.4285714 g NO rounds to 186 g NO due to significant figures
86. Generated by the cubic t(n) = n3 - 5n2 + 9n - 4 for n = 1, 2, 3, ...
There are two possible mole ratios in the balanced equation: 4 moles of NH3 to 6 moles of NO, and 5 moles of N2 to 6 moles of H2O.
The reaction equation for the oxidation of acetylene (C2H2) with nitrous oxide (N2O) is: 2C2H2 + N2O -> 2CO2 + H2O + N2
There are infinitely many rules that can generate this sequence. As imple one is Un = 5n2 - 21n +72 for n = 1, 2, 3, ... And then n = 4 gives U4 = 68