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How many grams of NO are required to produce 145g of N2 in the following reaction 4nh3 plus 6no 5n2 plus 6h20?
Wiki User
∙ 14y ago
4NH3 + 6NO -> 5N2 + 6H2O
145 g N2 x (1 mol/28.0 g) x (6 mol NO/5 mol N2) x (30.0 g NO/1 mol NO) = 186.4285714 g NO
rounds to 186 g NO due to significant figures
Wiki User
∙ 14y ago
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