(x - 2)(x - 4)
If that's 2x2, the answer is (x + 2)(x2 + 4)
(x-8)(x+8) = x2-64
x2-64 = (x-8)(x+8) when factored
x2+5x-24=0(x+8)(x-3)=0x=-8 x=3
x2 + 6x + 8 =(x + 2)(x +4)
(X + 2)(X + 4) Factored
(x - 2)(x - 4)
x3 + 3x2 - 6x - 8 = (x - 2)(x2 + 5x + 4) = (x - 2)(x + 1)(x + 4)
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
-((x + 2)(x - 8))
(x - 4)(x - 2)
x2-6x+8 = (x-2)(x-4) when factored
x^2+6x-16 (x+2)+(6x-16) x+8+x-16 (x+8)(x-2) here you go :)
If you mean: x2+6x+8 then it is (x+4)(x+2) when factored
2x2 + 6x - 8 = 72 ∴ 2x2 + 6x + 64 =0 ∴ x2 + 3x + 32 = 0 This can not be factored, as x is not equal to any integer. Using the quadratic equation, we find that: x = -3/2 ± √119 / 2i