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One way to do it:

x + (x+2) + (x+4) = 42

3x + 6 = 42

3x = 36

x = 12

The integers are: 12, 14, and 16

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Another way to do it:

Three consecutive even numbers add up to 42.

Their average is (42/3) = 14, so that's the one in the middle.

They are: 12, 14, and 16

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Q: Find 3 consecutive even integers that have a sum of 42?
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