One way to do it:
x + (x+2) + (x+4) = 42
3x + 6 = 42
3x = 36
x = 12
The integers are: 12, 14, and 16
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Another way to do it:
Three consecutive even numbers add up to 42.
Their average is (42/3) = 14, so that's the one in the middle.
They are: 12, 14, and 16
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No. There is no set of three consecutive even integers with a sum of 40.
The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.
There are two consecutive even integers. The numbers are 118 and 120.
They are -12, -10 and -8.
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