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Let the first integer be x.

then x + (x+1) + (x+2) + (x+3) = 290

4x + 6 = 290

4x = 284

x = 71

so the nanswer is 71+72+73+74 = 290

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2010-03-22 16:30:14
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Q: Find four consecutive integers whose sum is 290?
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