It is -7,-6,-5,-4!
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The sum is four.
The integers are 17, 19, 21 and 23.
No.Let the four numbers be (n-1), n, (n+1), (n+2).Their sum is 4n + 2 = 2(2n + 1)If 2000 is the sum of four consecutive integers, then:2(2n+1) = 2000⇒ 2n + 1 = 1000⇒ 2n = 999but 999 is odd, not even and so n cannot be an integer; therefore 2000 is not the sum of four consecutive integers.
The numbers are -11, -10, -9 and -8.
17 , 19 , 21 and 23 are the odd integers whose sum is 80 and the least integer is 17