Q: Find the product of prime factors 27?

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To find the greatest common factor (GCF) of 27, 63, and 108, we first need to find the prime factors of each number. The prime factors of 27 are 3 x 3 x 3, the prime factors of 63 are 3 x 3 x 7, and the prime factors of 108 are 2 x 2 x 3 x 3 x 3. The GCF is the product of the common prime factors raised to the lowest power they appear in all the numbers, which in this case is 3 x 3 = 9. Therefore, the greatest common factor of 27, 63, and 108 is 9.

The factors of 27 are: 1, 3, 9, and 27.The only prime factor of 27 is: 3.The factors of 34 are: 1, 2, 17, and 34.The prime factors of 34 are: 2 and 17.

Prime factorization of 27 = 3x3x3

The factors of 35 are 1, 5, 7, and 35. The factors of 27 are 1, 3, 9, and 27. The only factor they have in common is 1; therefore, 35 and 27 are relatively prime. Alternatively, you can look at the prime factors. The prime factors of 35 are 5 and 7. The prime factors of 27 are 3, 3, and 3. They have no prime factors in common, so they are relatively prime, which means their only common factor is 1.

The factors of 27 are 1,3,9,27 It's NOT prime it IS composite

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The number 27 has only one prime factor: 3.

27 = 3 x 3 x 3

As a product of its prime factors: 2*2*5*11*683 = 150260 As a product of its prime factors in exponents: 27*3*52*7 = 67200

3 x 3 x 3 = 27

To find the GCF of two numbers, you first need to express them as the product of their prime factors. For 14 and 27, this is: 14 = 2x7 27 = 3x3x3 The next step would be to identify any common factors. In this case, however, there are no common prime factors. Therefore, the GCF of 14 and 27 is 1.

It is: 27*59*71 = 1,750,000,000

To figure this out you should first express the numbers as the product of their prime factors: 27 = 3x3x3 45 = 3x3x5 The next step is to identify any common prime factors. Both numbers have two 3s as prime factors. Multiply these together and you get: 3x3 = 9 Thus 9 is the HCF of 27 and 45.

To find the common factors of 27 and 108, you should first break them down into their prime factors: 27 = 3x3x3 108 = 2x2x3x3x3 The next step is to identify any common factors. In this case, both numbers have three 3s as prime factors. Thus any product combination of these will give a number that is a common factor of 27 and 108. Thus the numbers that go into 27 and 108 are: 1, 3, 9 and 27.

As a product of its prime factors in exponents: 27*3 = 384

The factors of 27 are: 1, 3, 9, and 27.The only prime factor of 27 is: 3.The factors of 34 are: 1, 2, 17, and 34.The prime factors of 34 are: 2 and 17.

27 has the factors 1,3,9 & 27.... only 1 & 3 are prime.

The prime factor of 27 is 3. The prime factors of 26 are 2 and 13.