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403÷8 gives 50 as quotient and 3 as remainder.

Dividend- remainder=divisor ×quotient

403-3=8*50 which is 400. our value is 403

So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.

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Karuna Saravana

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4mo ago
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10y ago

The smallest number which must be added to 403 to make it exactly divisible by 8 is 5

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Q: Find the smallest number which must be added to 403 to make it exactly disvivible by 8?
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