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339 + 1 = 340,

which is exactly divisible.

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Q: What is the smallest number that must be added to 339 to make it exactly divisible?

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6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).

Add 7 cents to 2.45 . Now you have 2.52, which can be divided into 9 equal shares of 28 cents each.

124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.

What number must be added to to make it equal to 190312

10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor&times; quotient so 10056-5=23&times;437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23&times;438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23

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Seven

403÷8 gives 50 as quotient and 3 as remainder. Dividend- remainder=divisor ×quotient 403-3=8*50 which is 400. our value is 403 So increase divisor 8*51=408. 403+5 gives 408. So 5 must be added to 403 to get a no divisible by 8.

6. To check for divisibility by 9, add the digits of the number together and if the sum is divisible by 9, then the original number is divisible by 9. If the test is repeated on the sum(s) until a single digit remains, then this is the remainder when the original number is divided by 9. Subtracting this remainder from 9 will give the smallest number that needs to be added to to the original number to make it divisible by 9. For 75: 7 + 5 = 12 1 + 2 = 3 so 75 ÷ 9 has a remainder of 3, therefore add 9 - 3 = 6 to 75 to make it divisible by 9. (75 + 6 = 81 = 9 x 9).

It is 20 because 5220/180 = 29

It is 8961 - W*int(8961/W)

5621/12 =468 quotient ,5 remainder Next possibility increase quotient 469*12 gives 5628 now compare both their difference that is 5628-5621=7 so 7 must be added.

Add 7 cents to 2.45 . Now you have 2.52, which can be divided into 9 equal shares of 28 cents each.

124/3 = 41 quotient, remainder 1 Increase quotient 42*3 = 126. difference of 126 and 124 is 2 . So 2 is to be added it is least.

What number must be added to to make it equal to 190312

9400÷65 gives144 quotient,40 remainder. 65×145 =9425 25 is the least

10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor&times; quotient so 10056-5=23&times;437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23&times;438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23

Answer: 2A number is divisible by 3 if the sum of its digits is a multiple of 3.Now 2+1+4=7. If we add 2 more it is 9 which is a multiple of 3.So 216 is divisible by 3 since 2+1+6=9 which is a multiple of 3.