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Probably the best way is to change the complex number to its polar form, [or the A*eiΘ form] A is the magnitude or the distance from the origin to the point iin the complex plane, and Θ is the angle (in radians) measured counterclockwise from the positive real axis to the point. To find the square root of a number in this form, take the positive square root of the magnitude, then divide the angle by 2. Since there will always be 2 square roots for every number, to find the second root, add 2pi radians to the original angle, then divide by 2.

Take an easy example of square root of 4. Which we know is 2 and -2. OK so the magnitude is 4 and the angle is 0 radians. zero divided by 2 is zero, and the positive square root of 4 is 2. Now for the other square root. Add 2pi radians to 0, which is 2pi, then divide by 2, which is pi. pi radians [same as 180°] points in the negative real direction (on the horizontal), so we have ei*pi = -1 and then multiply by sqrt(4) = -2.

Try square root of i. i points straight up (pi/2 radians) with magnitude of 1. So the magnitude of the square root is still 1, but it points at pi/4 radians (45°). Converting back to rectangular gives you sqrt(2)/2 + i*sqrt(2)/2. The other square root will always point in the opposite direction [180° or pi radians]. So the other square root is at 225° or 5pi/4 radians, and the rectangular for this is -sqrt(2)/2 - i*sqrt(2)/2. Using FOIL (from Algebra) you can multiply it out like two binomials and you will get i when you square either of the two answers for square root.

Q: Find the square root of a complex number system?

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Math.sqrt(number) function is used to find the square root of a number.. try it

To find the complex conjugate of a number, change the sign in front of the imaginary part. Thus, the complex conjugate of 14 + 12i is simply 14 - 12i.

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This is best done if the complex number is in polar coordinates - that is, a distance from the origin, and an angle. Take the square root of the argument (the absolute value) of the complex number; and half the angle.

You can square any real number (complex ones too) so the domain is all real numbers.

The fourth square root is the 16th root of a number. On a computer, to find the 16th root of a number, say 5.6, enter 5.6^(1/16). If the number you start with is positive, you will have 2 real roots (one positive and one negative) and 14 complex roots. If it is negative, you will have 16 complex roots.

There are two solution: -3 and +2.

x2 + 4 = 0 then get the x on one side. x2 = -4 then find the square root of both which would cancel the square on the x. therefore the answer is: x = the square root of -4 = i squared root 4, which is a complex number ( imaginary number) since you cannot find the square root of oa negative number

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The square of a "normal" number is not negative. Consequently, within real numbers, the square root of a negative number cannot exist. However, they do exist within complex numbers (which include real numbers)and, if you do study the theory of complex numbers you wil find that all the familiar properties are true.

The square of any real number cannot be negative. However, there are equations whose solutions require the square root of negative numbers. The real number system was extended to the set of complex number to allow such operations. In some ways, this is analogous to the set of integers being extended to the set of rational numbers to allow division (when the denominator was not a factor of the numerator), or the set of rational numbers being extended to real numbers to allow square (and other) roots.

square root it

It is the number that youve hat to square to get to that number.

find the smallest number by which 9408 must be multiplied to get a perfect square/ also find the square of the number

To find a square number, you have to times a number, for example 4 only once. So the square number will be 16 because you timed 4x4.