This problem can be solved with a system of equations. Let the first number equal x and the second number equal y. Here are the two equations: x-y=8 This makes sense because if two number have a difference of 8, than the first number minus the second number will equal 8. x * Y = 48 This is self explanatory. Now, we solve: x-y=8 x=8+y (y is added to both sides. Now we know what x is equal to, so we can substitute it into the second equation) (8+y)*y=48 8y+y2=48 (y is distributed) y2+8y-48=0 (the equation is made into a quadratic) (y+12)(y-4)=0 (the equation is factored) We know y is equal to four and not -12 because both number are positive. Now we solve for x: x-4=8 x=12 Therefore, your two number are 12 and 4.
12=(15/100)x x=[(12)(100)]/15=(20)(4)=80 Now, 35 percent of a number is (35/100)(80)=Y after cancelling, Y=(7)(4)=28 OR (Shorthand Version) 12/.15=80 80(.35)=28
To find a percent of a number would be by changing that percent into a decimal to multiplying that number. 100% of 16 = 16, and 20% of 16 = 0.2 x 16 = 3.2. Then 16 + 3.2 = 19.2 is 120% of 16.
40% of 10 y = 40/100 of 10y =4y
The answer is 111 1/9%
x + y = 48
cuarenta y ocho cuarenta y ocho cuarenta y ocho
The numeral 48 is spelled forty-eight.
Cuarenta y ocho
x=number 1, y=number 2 {x-y=20} {x+y=48} x=y+20 y+20+y=48 2y=28 [y=14] x=14+20 [x=34]
60% of y = y * 0.6
4 & 8 Watch me closely. X + Y = 12 AND X^2 - Y^2 =48 Solve 1st equation for X ; X = 12 - Y Substitute into 2nd equation [12 - Y]^2 - y^2 = 48 144 - 24Y + Y^2 - Y^2 = 48 144 - 24Y = 48 24Y = 96 Y = 4 and X = 8
Cincuenta y cinco is the number 55 (fifty-five).
0.34*y
It is the same number. y*100%=y*1=y.
4x.12 = .48 = 12/25
Let's call the larger number x and the smaller number y. From the information given, we have the equations x + y = 80 and x - y = 16. Solving these equations simultaneously gives x = 48 and y = 32. Therefore, the two numbers are 48 and 32.