0
Still curious? Ask our experts.
Chat with our AI personalities
Jordan
Professor
LaoAdd your answer:
Earn +20 pts
Two positive numbers have a difference of 8 and a product of 48 Find the two numbers?
This problem can be solved with a system of equations. Let the first number equal x and the second number equal y. Here are the two equations: x-y=8 This makes sense because if two number have a difference of 8, than the first number minus the second number will equal 8. x * Y = 48 This is self explanatory. Now, we solve: x-y=8 x=8+y (y is added to both sides. Now we know what x is equal to, so we can substitute it into the second equation) (8+y)*y=48 8y+y2=48 (y is distributed) y2+8y-48=0 (the equation is made into a quadratic) (y+12)(y-4)=0 (the equation is factored) We know y is equal to four and not -12 because both number are positive. Now we solve for x: x-4=8 x=12 Therefore, your two number are 12 and 4.
What is 35 percent of a number if 12 is 15 percent of a number?
12=(15/100)x x=[(12)(100)]/15=(20)(4)=80 Now, 35 percent of a number is (35/100)(80)=Y after cancelling, Y=(7)(4)=28 OR (Shorthand Version) 12/.15=80 80(.35)=28
What number is 40 percent of 10y?
40% of 10 y = 40/100 of 10y =4y
If x is 90 percent of y then y is how much percent of x?
The answer is 111 1/9%
Is x percent of y equal to y percent of x?
Let [x percent of y] = (x/100)*y. And [y percent of x] = (y/100)*x.Use the ruSo the first one (x/100)*y = y*(x /100) = y*x/100.The second one: (y/100)*x = x*(y/100) = x * y / 100, which equals y*x/100.So yes they equal the same thing, so they are equal.
