You cannot show it in general since it need not be true!
An equilateral triangle is always inscribed in a circle.This means that if you can prove that z1, z2 and z3 are the vertices of an equilateral triangle, they automatically lie on a circle subscribing it.Compute |z1-z2|, |z1-z3| and |z2-z3|. These need to be equal for z1, z2 and z3 to lie on an equilateral triangle. If not, they aren't lying on an equilateral triangle.for z=a+ib, |z| = (a^2+b^2)^(1/2).To find the center c of the circle, note that (z1-c)+(z2-c)+(z3-c) = 0, hence,c = (z1+z2+z3)/3.
1.00
No. Not can it have an odd number of vertices.
No. A pyramid can have any number of vertices from 4 upwards.
no
An equilateral triangle inscribed in a circle has three sides that are equal in length and three angles that are each 60 degrees. The center of the circle is also the intersection point of the triangle's perpendicular bisectors.
An isosceles triangle and an equilateral triangle both have three vertices.
true
The triangle that has all three vertices touching the circle is called an 'inscribed triangle.' The circle has no special name, only the polygon inscribed.
There are only 5 known regular Platonic solids and they and their properties are:- 1 Tetrahedron: (pyramid) 4 equilateral triangle faces, 6 edges and 4 vertices 2 Hexahedron (cube) 6 square faces, 12 edges and 8 vertices 3 Octahedron: 8 equilateral triangle faces, 12 edges and 6 vertices 4 Dodecahedron: 12 regular pentagon faces, 30 edges and 20 vertices 5 Icosahedron: 20 equilateral triangle faces, 30 edges and 12 vertices All of them can be inscribed inside a sphere.
An equilateral triangle has 3 lines of symmetry which perpendicularly bisects each of its vertices
A triangle has 3 vertices and three sides (edges). It has one face.
An equilateral triangle is always inscribed in a circle.This means that if you can prove that z1, z2 and z3 are the vertices of an equilateral triangle, they automatically lie on a circle subscribing it.Compute |z1-z2|, |z1-z3| and |z2-z3|. These need to be equal for z1, z2 and z3 to lie on an equilateral triangle. If not, they aren't lying on an equilateral triangle.for z=a+ib, |z| = (a^2+b^2)^(1/2).To find the center c of the circle, note that (z1-c)+(z2-c)+(z3-c) = 0, hence,c = (z1+z2+z3)/3.
Tetrahedron: 4 equilateral triangle faces and 4 vertices.
3 vertices in a triangle, whether it is equilateral, isosceles or scalene; acute angled, right or obtuse.
3(All triangles have 3 vertices)
All triangles have 3 sides and 3 vertices.