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The center of the circumscribed circle about a triangle is equidistant to the vertices of the inscribed triangle?
Wiki User
∙ 14y ago
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Wiki User
∙ 14y ago
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How can you tell if a regular shape will tessellate?
It will tessellate if its vertices divide into 360 degrees evenly. The only regular polygons that will tessellate are an equilateral triangle, a square and a regular hexagon. There are other, non-regular, polygons that will tessellate.
Why is the point on a cone a vertex?
Because it's singular for vertices
Is it possible for a polygon to have 83 diagonals?
If a polygon had 166 sides it would have 83 diagonals as each diagonal must join two vertices.
A polygon has 20 diagonals how many sides does it have?
It is an octagon with 8 sides. Let n be the number of sides = number of vertices. Then each vertex can be connected to n-3 other vertices, giving n(n -3) connections. However, this counts each vertex pair connection twice, so there are: n(n - 3) / 2 diagonals. Thus if there are 20 diagonals: n(n - 3) / 2 = 20 n2 - 3n = 40 n2 - 3n - 40 = 0 (n + 5)(n - 8) = 0 so n = -5 or 8. As a polygon cannot have a negative number of sides, n = 8.
How do you find the vertex of an absolute value function?
There are three main types of vertices for an absolute value function. There are some vertices which are carried over from the function, and taking its absolute value makes no difference. For example, the vertex of the parabola y = 3*x^2 + 15 is not affected by taking absolute values. Then there are some vertices which are reflected in the x-axis because of the absolute value. For example, the vertex of the absolute value of y = 3*x^2 - 15, that is y = |3*x^2 - 15| will be the reflection of the vertex of the original. Finally there are points where the function is "bounced" off the x-axis. These points can be identified by solving for the roots of the original equation. -------------- The above answer considers the absolute value of a parabola. There is a simpler, more common function, y = lxl. In this form, the vertex is (0,0). A more general form is y = lx-hl +k, where y = lxl has been translated h units to the right and k units up. This function has its vertex at (h,k). Finally, for y = albx-hl + k, where the graph has been stretched vertically by a factor of a and compressed horizontally by a factor of b, the vertex will be at (h/b,ak). Of course, you can always find the vertex by graphing, especially since you might not remember the 2nd or 3rd parts above.
Is the shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is the circles radius?
True
The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is the circle's radius?
True
Which point in a triangle is equidistant from the vertices's of the triangle?
Not sure about vertices's. The circumcentre is equidistant from a triangle's vertices (no apostrophe).
What is the center of a circumscribed cirlce of a triangle called?
It is called the circumcenter of the triangle. . The circumcenter is equidistant from the three vertices, and so the common distance is the radius of a circle that passes through the vertices. Another name for it is the circumcircle
Is the centroid equidistant from the vertices's of a triangle?
No. and it is not vertices's! vertices will do.
The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is the circles radius?
False apex q
Whhat is the difference between an inscribed and an circumscribed shape?
Inscribed has the vertices n the circle.Circumscribed has the sides tangent to the circle.
Is the circumvention is equidistant from the vertices's of a triangle?
Circumvention means to surround or to go around or bypass. It is not a geometric term and has nothing whatsoever to do with a triangle. The circumcentre is equidistant from the vertices (not vertices's!).
The circumcenter of a triangle is the point equidistant from the vertices of the triangle?
True
What is the circumcenter theorem?
The circumcenter of a triangle is equidistant from the vertices of a triangle.
What is the Circumcenter Conjecture?
The circumcenter of a triangle is equidistant from the vertices.
What is the part of the triangle that is equidistant from the vertices of the triangle?
The centroid, which is the point where the medians meet.
