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There are more real numbers than integers. The set of integers is countably infinite, of magnitude aleph-zero. The set of real numbers is uncountably infinite (specifically, aleph-one).

A computer can't really represent real numbers (that would require an infinite amount of memory), rather, it uses an approximation.

There are more real numbers than integers. The set of integers is countably infinite, of magnitude aleph-zero. The set of real numbers is uncountably infinite (specifically, aleph-one).

A computer can't really represent real numbers (that would require an infinite amount of memory), rather, it uses an approximation.

There are more real numbers than integers. The set of integers is countably infinite, of magnitude aleph-zero. The set of real numbers is uncountably infinite (specifically, aleph-one).

A computer can't really represent real numbers (that would require an infinite amount of memory), rather, it uses an approximation.

There are more real numbers than integers. The set of integers is countably infinite, of magnitude aleph-zero. The set of real numbers is uncountably infinite (specifically, aleph-one).

A computer can't really represent real numbers (that would require an infinite amount of memory), rather, it uses an approximation.

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There are more real numbers than integers. The set of integers is countably infinite, of magnitude aleph-zero. The set of real numbers is uncountably infinite (specifically, aleph-one).

A computer can't really represent real numbers (that would require an infinite amount of memory), rather, it uses an approximation.

Q: How and why are real numbers more difficult to represent and process than integers?

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They are:Replace the numbers in the question with approximate valuesCarry out the calculation using them instead of the exact numbers.

== Will you please answer my question?! Will you please answer my question?! == In number theory ( http://www.answers.com/topic/number-theory ), integer factorization is the process of breaking down a composite number ( http://www.answers.com/topic/composite-number ) into smaller non-trivial integers ( http://www.answers.com/topic/divisor-2 ), which when multiplied together equal the original integer. Source:integer-factorization== The prime factors of a positive integer are the prime numbers that divide into that integer exactly, without leaving a remainder.The process of finding these numbers is called integer factorization, or prime factorization. Source:http://en.wikipedia.org/wiki/Prime_factor

Both result from the comparison of integers. The process used to find them is the same. The only difference is in their function. One is a denominator, one isn't.

Yes. You know this is true because you learned a process-- an "algorithm"--for adding two numbers together, and if you start with two whole numbers, the result is also a whole number.

If you are making use of long division method, the process of dividing a whole number is actually a subset of the process of dividing the decimals. While dividing both you may get a quotient with decimal places. Some exceptions to this do exist in case of whole numbers. Like when you are dividing 100 by 2, the quotient 50 has no decimal places.

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One misconception is that the process is difficult.

integers are negative and poitive numbers you can multipy and divide poitive numbers but you can't divide negative numbers because you can't have negitve divded by a other number

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The process is difficult because of communication problem.

Multiplication

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The product of two integers is found by multiplying them. Eg. the product of 5 and 3 is 15.

No, ENIAC could store only 20 numbers of 10 digits length. All other numbers were constants set on switches by hand. It takes thousands of numbers per second of sound and millions of numbers per second of a movie.

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You do not "solve" rational numbers. Rational numbers are not a puzzle nor a question nor an equation, so there is nothing to solve. The question is like asking how do you solve a person's name.

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