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First you find a common multiple of the denominators. The least common denominator is handy but not essential. This number will be the denominator of the answer - before simplification.

For both fractions find an equivalent fraction whose denominator is this common denominator.

Carry out the subtraction on the new numerators to give the numerator of the answer.

Simplify the result for the final, simplified answer.

First you find a common multiple of the denominators. The least common denominator is handy but not essential. This number will be the denominator of the answer - before simplification.

For both fractions find an equivalent fraction whose denominator is this common denominator.

Carry out the subtraction on the new numerators to give the numerator of the answer.

Simplify the result for the final, simplified answer.

First you find a common multiple of the denominators. The least common denominator is handy but not essential. This number will be the denominator of the answer - before simplification.

For both fractions find an equivalent fraction whose denominator is this common denominator.

Carry out the subtraction on the new numerators to give the numerator of the answer.

Simplify the result for the final, simplified answer.

First you find a common multiple of the denominators. The least common denominator is handy but not essential. This number will be the denominator of the answer - before simplification.

For both fractions find an equivalent fraction whose denominator is this common denominator.

Carry out the subtraction on the new numerators to give the numerator of the answer.

Simplify the result for the final, simplified answer.

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12y ago

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First you find a common multiple of the denominators. The least common denominator is handy but not essential. This number will be the denominator of the answer - before simplification.

For both fractions find an equivalent fraction whose denominator is this common denominator.

Carry out the subtraction on the new numerators to give the numerator of the answer.

Simplify the result for the final, simplified answer.

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Wiki User

12y ago
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Q: How are equivalent fractions used when subtracting unlike fractions?
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