Q: How do you express the prime factors of 80 in index form?

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Prime factors of 1080 are 23 33 5.

To express 160 in index form using prime factors, we first need to find the prime factors of 160. Breaking down 160 into its prime factors, we get 2^5 * 5. Therefore, in index form, 160 can be written as 2^5 * 5.

To express 63 as a product of prime factors in index form, we first need to find the prime factors of 63. 63 can be factored as 3 x 3 x 7. This can be written in index form as 3^2 x 7. Therefore, 63 as a product of prime factors in index form is 3^2 x 7.

360 = 2 x 2 x 2 x 3 x 3 x 5 = 23 x 32 x 5

2^4 x 3 x 5

Related questions

Prime factors of 1080 are 23 33 5.

360 = 2 x 2 x 2 x 3 x 3 x 5 = 23 x 32 x 5

2^4 x 3 x 5

120 = 23 x 3 x 5

The prime factors of 45 are 3 and 5.

648 expressed as a product of its prime factors in index form is 2^3 times 3^4

24 as a product of its prime factors in index form: 2| 24 === 2| 12 === 2| 6 === .....3 Prime factorization of 24= 2 x 2 x 2 x 3

52 = 25

300

360= 23 times 45

72 *23

23 x 33 = 216