This is the prime factorization of 80 in index form: 80 = 2 x 2 x 2 x 2 x 5 = 24 x 5
Prime factors of 1080 are 23 33 5.
To express 63 as a product of prime factors in index form, we first need to find the prime factors of 63. 63 can be factored as 3 x 3 x 7. This can be written in index form as 3^2 x 7. Therefore, 63 as a product of prime factors in index form is 3^2 x 7.
360 = 2 x 2 x 2 x 3 x 3 x 5 = 23 x 32 x 5
2^4 x 3 x 5
120 = 23 x 3 x 5
Prime factors of 1080 are 23 33 5.
To express 63 as a product of prime factors in index form, we first need to find the prime factors of 63. 63 can be factored as 3 x 3 x 7. This can be written in index form as 3^2 x 7. Therefore, 63 as a product of prime factors in index form is 3^2 x 7.
360 = 2 x 2 x 2 x 3 x 3 x 5 = 23 x 32 x 5
2^4 x 3 x 5
To express 144 as a product of its prime factors in index form, we first find the prime factors of 144, which are 2 and 3. 144 can be written as 2^4 * 3^2 in index form, where 2 is raised to the power of 4 and 3 is raised to the power of 2. This shows that 144 can be expressed as the product of its prime factors in index form.
120 = 23 x 3 x 5
648 expressed as a product of its prime factors in index form is 2^3 times 3^4
120 = 2 x 2 x 2 x 3 x 5 = 23 x 3 x 5
Well, isn't that just a happy little question! To write 160 as a product of its prime factors, we can express it as 2^5 * 5. In index form, this would be written as 2^5 * 5^1. Just remember, there are no mistakes, only happy little accidents in math!
24 as a product of its prime factors in index form: 2| 24 === 2| 12 === 2| 6 === .....3 Prime factorization of 24= 2 x 2 x 2 x 3
52 = 25
300