6x2 + 7x - 5 = (3x + 5)(2x - 1)
To factor a monomial, is to write the monomial as the product of two monomials. there are more than one possible answers when factoring For example if you had: 6x4 the answer could be -(2x3)(3x) -(2x2)(3x2) -(6x)(x3) -(x)(6x3) -(6x2)(x2)
The expression may be : 6x2 + 17x + 12 This factors as, 6x2 + 17x + 12 = (3x + 4)(2x + 3) Or, the expression could be : 6x2 - 17x + 12 This factors as, 6x2 - 17x + 12 = (3x - 4)(2x - 3)
6(x2 -4x - 12) 6(x-6)(x+2)
1x12, 2x6, 3x4, 4x3, 6x2 1x12 1x12, 2x6, 3x4, 4x3, 6x2 1x12
-3x3 - 6x2 + 189x = -3x(x2 + 2x - 63) = -3x(x + 9)(x - 7)
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
(3x - 5x) + (x2 - 6x2) = -2x -5x2 = -x(2 + 5x)
The GCF for the numerical part is 2 . The factors for x2 are xâ‹…x x â‹… x . The factor for x1 is x itself
2x(x2 + 3x - 7)
6x2=12 2x-28=?
6x2 + 10x = 2x(3x + 5)
6x2-24=0 6(x2-4)=0 x= {-2,2}
First divide by 6: 6(x2 - 3x + 2) = 6(x - 1)(x - 2)
3x(x2 + 2x - 4)
10x2 - 56 = 88 - 6x2 : 10x2 + 6x2 = 88 + 56 : 16x2 = 144 : x2 = 9 : x = ± 3
x^2 -5x-6 factors to: (x-6)(x+1)