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What else can I help you with?
How do you factor x to the sixth minus y to the sixth?
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
How do you factor x3 plus x2-3x-3?
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
How would you factor x3 plus 343?
(x + 7)(x2 - 7x + 49)
Factor completaly x3 plus 2x3 plus 4xplus 8?
If that's 2x2, the answer is (x + 2)(x2 + 4)
What is factor x3-343?
x3-343
How do you factor x3 plus y3 divide x plus y?
x^2 - xy + y^2
What x3 plus y3 called?
It is an algebraic expression.
How do you factor x to the sixth minus y to the sixth?
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
How to factirise this x3 y3 equation?
x3-y3
Factor completely x3-y3?
(x - y)(x^2 + xy + y^2
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
What is the answer to x plus y to 3rd power plus x minus y to 3rd power?
(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
When can a polynomial is said to be sum or difference of two cubes?
When it is of the form x3 + y3 or x3 - y3. x or y can have coefficients that are perfect cubes, or even ratios of perfect cubes eg x3 + (8/27)y3.
What is the solution to x3 plus 1331 equals y3?
One equation with two unknowns usually does not have a solution.
Is y-1 is a factor of y3-19y plus 30?
No.
How do you factor x3 - y3?
0
Whats y3+x3+z3 equals to?
3xyz
