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The distance between points x1 y1 and 5 -5 is the square root of x1 plus 5 2 plus y1 - 52?
false
The distance between points (x1 y1) and (4 8) is the square root of (x1 - 8)2 plus (y1 - 4)2.?
It is false-apex
What formula with functions can you enter to calculate the range of values in Y1 to Y10?
There are many calculations that could be done: =SUM(Y1:Y10) =AVERAGE(Y1:Y10) =MAX(Y1:Y10) =MIN(Y1:Y10) =COUNT(Y1:Y10)
What is 5x-y1?
5x-y1 = 4
What is the equation of the curve yx2 plus 2x plus 1 when y1?
Without an equality sign the given terms of an expression can't be considered to be an equation and so therefore no solution is possible.
The distance between points (1 2) and (x1 y1) is the square root of (x1 - 1)2 plus (y1 - 2)2.?
The distance between the points (1, 2) and (x1, y1) is calculated using the distance formula, which is derived from the Pythagorean theorem. Specifically, the distance ( d ) is given by ( d = \sqrt{(x1 - 1)^2 + (y1 - 2)^2} ). This expression represents the length of the line segment connecting the two points in a Cartesian plane.
How can you find the length of a line segment in the coordinate plane?
The formula is the square root of: (x2-x1)^2 plus (y2-y1)^2
C program to design a car?
#include<stdio.h> #include<graphics.h> #include<math.h> #include<conio.h> #include<dos.h> #include<alloc.h> #include<stdlib.h> #define RAD 3.141592/180 class fig { private: int x1,x2,y1,y2,xinc,yinc; public: void car() { xinc=10;yinc=10; x1=y1=10; x2=x1+90;y2=y1+35; int poly[]={x1+5,y1+10,x1+15,y1+10,x1+20,y1,x1+50,y1,x1+60,y1+10,x1+90,y1+17,x1+90,y1+20,x1+5,y1+20,x1+5,y1+10}; setfillstyle(SOLID_FILL,LIGHTGRAY); setlinestyle(SOLID_LINE,1,2); setcolor(4); drawpoly(9,poly); line(x1+15,y1+10,x1+60,y1+10); line(x1+20,y1+10,x1+20,y1); line(x1+35,y1+10,x1+35,y1); line(x1+50,y1+10,x1+50,y1); floodfill(x1+18,y1+8,4); floodfill(x1+28,y1+8,4); floodfill(x1+36,y1+8,4); floodfill(x1+52,y1+8,4); setfillstyle(SOLID_FILL,4); floodfill(x1+18,y1+12,4); setfillstyle(SOLID_FILL,BLUE); bar(x1+5,y1+20,x1+90,y1+25); setcolor(DARKGRAY); circle(x1+20,y1+25,8); circle(x1+20,y1+25,6); setfillstyle(1,8); floodfill(x1+21,y1+25,8); circle(x1+70,y1+25,8); circle(x1+70,y1+25,6); floodfill(x1+71,y1+25,8); int size=imagesize(x1,y1,x2,y2); void far *buf=farmalloc(size); getimage(x1,y1,x2,y2,buf); while(!kbhit()) { putimage(x1,y1,buf,XOR_PUT); x1+=xinc;x2+=xinc; if(x2<(getmaxx()-10)) putimage(x1,y1,buf,COPY_PUT); else { cleardevice(); x1=10;x2=x1+90; y1+=yinc;y2+=yinc; if(y2<(getmaxy()-10)) { putimage(x1,y1,buf,COPY_PUT); } else {y1=10;y2=y1+35;} } delay(200); } farfree(buf); getch(); } } } } void main() { int gd=DETECT,gm; initgraph(&gd,&gm,"d:\\cplus"); fig f; f.car(); cleardevice(); closegraph(); }
How do you draw a square using line command?
Line (x1, y1, x2, y1); Line (x2, y1, x2, y2); Line (x2, y2, x1, y2); Line (x1, y2, x1, y1);
Is the equation x plus y equals 4 linear or not?
It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
What is the answer to 3x y1 x y1?
{3x +y =1 {x+y= -3
How Do You Solve Y2-5Y plus 4 equals 0?
Y²-5Y+4=0 Y1=-(-5/2) - Square root of ((-5/2)²-4) Y1= 2.5 - Square root of 2.25 Y1 = 1 Y2=-(-5/2) + Square root of ((-5/2)²-4) Y2= 2.5 + Square root of 2.25 Y2 = 4 Y can be either 1 or 4
