2x + 5 =
2x and 6x
4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).4x^2 - ox - 25 = 4x^2 - 25 which is a difference of two squares (DOTS)= (2x)^2 - (5)^2So, the factorisation is (2x + 5)*(2x - 5).
6x plus 4y
1/x + 1/2x + 2 = 2/3; 3/2x = -4/3; -8x = 9 (2 + 1)/2x + 2 = 2/3 3 + 4x = 4x/3 9 + 12x = 4x 8x = -9 x = -1 1/8 which isn't an integer but fits the stated conditions If you're doing A+ the answer is 2.
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.
You make a table of x vs. y values. That is, you substitute some value for "x", and calculate the corresponding value for "y". Then you graph the points. The equations you give are straight lines, so two points are sufficient - in theory. It is recommended to include three points, as an additional check, in case you do something wrong.
-2x + y = 5 is a line and can have an infinite number of answers.if x=0 then y=5if x=1 then y=7If you graph these two points then draw a line through them you will have a graph of the points made of pairs of numbers that would make this statement true.
One way would be to graph the two equations: the parabola y = x² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)
-2x+3y=1 3y=1+2x y=(1+2x)/3 Then proceed to find points by plugging in given or arbitrary values of x.
-2
-2
-2x plus 3y equals 1
(0,4) and (-2, 0)
If you mean: 2x+4y = 4 then the graph joins the points: (2, 0) and (0, 1)
8
3