x2-64 = (x-8)(x+8)
No. Trial and error is the most inefficient way for factoring.
Multiplying.
It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.
Infinity
Yes
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When the co-efficient of x2 is 1
Solve by factoring. Solve by taking the square root of both sides.
Solve by factoring.2x2 - 3x + 1 = 0
-(x - 1)(x2 + x + 1)
X2 - Y2 = (X + Y)(X - Y)
The discriminant for the quadratic is b2-4ac = 302 - 4*4*45 = 900 - 720 = 180 Since 180 is not a perfect square, the roots of the equation are irrational and it is far from straightforward to solve such an equation by factoring.
It is easier to solve a quadratic equation by factoring when the equation can be expressed as a product of two binomials that easily yield integer roots. This method is often quicker for simpler quadratics with small coefficients. In contrast, using a table to find solutions can be more cumbersome and time-consuming, particularly for equations where the roots are not integers or when the quadratic is more complex. Thus, factoring is preferred when the equation allows for straightforward factorization.
Factoring is often considered the best way to solve mathematical problems, particularly polynomials, because it simplifies complex expressions into more manageable components. By breaking down a problem into its factors, you can identify solutions more easily and efficiently. This method also provides insights into the relationships between terms and can reveal properties of the equation, such as roots and intercepts. Additionally, factoring can reduce computational effort, making it a preferred approach in algebra and beyond.
x264: Without knowing the value of x you cannot evaluate this expression.
To solve a quadratic equation by factoring, first express the equation in the standard form ( ax^2 + bx + c = 0 ). Next, look for two numbers that multiply to ( ac ) (the product of ( a ) and ( c )) and add up to ( b ). Rewrite the middle term using these two numbers, then factor the quadratic expression into two binomials. Finally, set each binomial equal to zero and solve for ( x ).