write the number 14as a product of prime factor?
As a product of its prime factors: 2*2*2*2*3*5*5 = 1200
3 x 3 x 11
3 x 5 x 7 = 105
It is: 2*2*2*2*3 = 48
write the number 14as a product of prime factor?
The answer is 2 and 19 since there both prime.
As a product of its prime factors: 2*3*3*3*5 = 270
As a product of its prime factors: 2*2*2*2*3*5*5 = 1200
24 = 23 x 3
225 = 32 x 52
3 x 3 x 11
2 times 3 times 5
25 x 32
3 x 5 x 7 = 105
It is: 2*2*2*2*3 = 48
3 x 3 x 11 = 99