sorry i don't know but you can check your math book
-1, -3 and -8
The four even integers are 4, 6, 8, and 10. 10 x 8 = 80 6 x 4 = 24 80 - 24 = 56
If you solve by trial and error you can start with the sum of two consecutive odd integers. 5+7=12 no 7+9=16 no 9+11=20 no 11+13=24 yes. Then put the 4 numbers you're looking for 9, 11, 13, 15. Or you can use algebra logic. x+x+2=24 2x+2=24 2x=22 x=11 Then 9,11,13,15
There are 22 integers between them.
11, 13, 15 and 17(143 is 112 less than 255)The equation is (A)(A+2) = (A+4)(A+6) - 112A2 + 2A = A2 +10A +24 -1122A = 10A - 888A = 88A = 112,5,6
31
Two consecutive even integers will be one more and one less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is 25, so the two consecutive integers are 24 and 26.
They are two integers.
Their product is 143.
-10 and -14
The quotient of 6484 divided by 24 is 270.1667. This can be expressed as 270 with a remainder of 4, or approximately 270.17 when rounded to two decimal places.
They are 4 and 24
24 and 4
24 & 4
Write it down. All terminating decimals are rational.
Two integers can have only one sum, not two as required by the question.
-6 and -4.