-1, -3 and -8
The four even integers are 4, 6, 8, and 10. 10 x 8 = 80 6 x 4 = 24 80 - 24 = 56
If you solve by trial and error you can start with the sum of two consecutive odd integers. 5+7=12 no 7+9=16 no 9+11=20 no 11+13=24 yes. Then put the 4 numbers you're looking for 9, 11, 13, 15. Or you can use algebra logic. x+x+2=24 2x+2=24 2x=22 x=11 Then 9,11,13,15
is the set of integers greater than or equal to −7 and less than or equal to −1 =B−26, 24, 29
There are 22 integers between them.
31
Two consecutive even integers will be one more and one less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is 25, so the two consecutive integers are 24 and 26.
They are two integers.
Their product is 143.
-10 and -14
They are 4 and 24
24 & 4
24 and 4
Write it down. All terminating decimals are rational.
Two integers can have only one sum, not two as required by the question.
-6 and -4.
They are 48/24 = 2 or 24/12 = 2