sorry i don't know but you can check your math book
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-1, -3 and -8
The four even integers are 4, 6, 8, and 10. 10 x 8 = 80 6 x 4 = 24 80 - 24 = 56
If you solve by trial and error you can start with the sum of two consecutive odd integers. 5+7=12 no 7+9=16 no 9+11=20 no 11+13=24 yes. Then put the 4 numbers you're looking for 9, 11, 13, 15. Or you can use algebra logic. x+x+2=24 2x+2=24 2x=22 x=11 Then 9,11,13,15
There are 22 integers between them.
11, 13, 15 and 17(143 is 112 less than 255)The equation is (A)(A+2) = (A+4)(A+6) - 112A2 + 2A = A2 +10A +24 -1122A = 10A - 888A = 88A = 112,5,6