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If you solve by trial and error you can start with the sum of two consecutive odd integers. 5+7=12 no 7+9=16 no 9+11=20 no 11+13=24 yes.

Then put the 4 numbers you're looking for 9, 11, 13, 15.

Or you can use algebra logic.

x+x+2=24

2x+2=24

2x=22

x=11

Then 9,11,13,15

Q: Which correctly identifies 4 consecutive odd integers where the sum of the middle two integers is equal to 24?

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I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.

9,11,13

These are really simple to solve. Just divide by 3 and that gives you your middle integer. In this case 348/3 = 116 so the trio are 115, 116 and 117.

40 Ã· 5 = 8, so the average of the five numbers will be 8. That means that 8 will be in the middle. 6 + 7 + 8 + 9 + 10 = 40

You need to order them and then find the middle one (or the mean of the middle two).You need to order them and then find the middle one (or the mean of the middle two).You need to order them and then find the middle one (or the mean of the middle two).You need to order them and then find the middle one (or the mean of the middle two).

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The sum of three consecutive integers is -72

I think the answer is zero. The only 15 consecutive integers whose average is 7 are the integers 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14. For any odd number of consecutive integers the average will be equal to the middle number, and this is the only group of 15 consecutive integers with 7 as the middle number. The product of any group of numbers that includes 0 will always be 0 because 0 times anything is 0.

Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.

21, 23, 25. Reasoning: Call the unknown middle member of the three consecutive integers m. Then m - 2 + m + m+2 =69; 3m = 69; m = 23.

9, 11, 13, 15 The solution equation is A + B = 24 where B = A +2 (the consecutive odd integer) 2A +2 = 24 A = 11, B = 13

There are three consecutive integers. Let's call the middle one x. The one before it is x - 1 and the one after it is x + 1. Adding them together equals 3x. That means that whatever they equal has to be a multiple of 3. Since 176 is not divisible by 3, you will not be able to find three consecutive integers with that total.

Suppose the middle integer is a. Then the three consecutive integers are a-1, a and a+1. Now, 3*a = (a-1)+(a+1) + 1 So 3a = 2a + 1 => a=1 So the three numbers are 0, 1 and 2

9,11,13

Middle integer must be a third of 93 so integers are 30, 31 and 32.

153/3 = 51The middle number is 51, so the numbers are...50, 51 and 52

To do these problems the algebra way, make n the middle integer and call the 3 integers n-1, n, and n+1.(n-1) + n + (n+1) = -93simplifying the left side,3n = -93divide both sides by 3 to get n by itself ('isolate' n)n = -31So the 3 consecutive integers are -32, -31, and -30.-32, -31, -30

-1, 1 and 3