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5X-2y=4
Solve the simultaneous equations by eliminating one of the variables and solving for the other variable, substitute the found value back into one of the equations to solve for the eliminated variable, and then substitute both values found into the other equation as a check:3x + 2y = 5x + 2y = 7{1} - {2} → (3x - x) + (2y - 2y) = 5 - 7 → 2x = -2As there is 27 in both equations, subtract one from the other ({1}-{2}) and then solve {3}2x = -2→ x = -1Substituting back into equation {2}:x + 2y = 7-1 + 2y = 7→ 2y = 8→ y = 4Checking by substituting for x and y in {1}:3x + 2y = 53×-1 + 2×4 = -3 + 8 = 5 as required→ The required solution is x = -1, y = 4.
(5x-10)(x+3)
5x and 10x
2x2 + 5x + 3 Notice the first term, which can be rewritten as 2x times x. With this in mind, you can write the equation as...(2x + a)(x + b)...where -a and -b are the answers.You know that a times b is equal to 3.With a little trial and error, you will find:2x2 + 5x + 3 = (2x + 3)(x + 1)