write equation in standfrd form
y =mx + b where b = y intercept
5x - 2y =20
5x -20 = 2y
5/2 x -10 = y
when x = 0 y = -10, the y intercept
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5x - 2y = 05x - 5x - 2y = 0 - 5x-2y = - 5x(-2y)/-2 = (-5x)/-2y = (5/2)x where the slope is 5/2 and the y-intercept is 0.
2y = 5x - 10Putting into Slope-Intercept form, we have y = 5/2 x - 5. So, the y-intercept is -5 and the slope is 5/2 or 2.5. (x-intercept is 2).
If you mean 2y = -5x+14 then y = -2.5x+7 whereas -2.5 is the slope and 7 is the y intercept
5x-2y=11 -2y=-5x+11 y=(5/2)x - 11/2 Slope is 5/2
5x-2y=20 Subtract 5x on both sides to see what y equals. -2y=20-5x Divide by -2 on each side. y=-10+(5/2)x or y = (5/2)x - 10 (the slope-intercept form of the equation of a line, where the y-intercept is -10) Add 2y to both sides to see what x equals. 5x=20+2y Divide by 5 on each side. x=4+2/5y or x = (2/5)y + 4, where 4 is the x-intercept. (all this work is to show that when the value of y is zero, the line cuts the x-axis at 4) Now plug in what x equals into the equation of what y equals to get the exact value of y. y=-10+5/2x y=-10+5/2(4+2/5y) Distribute the 5/2 to the (4+2/5y) in parentheses. y=-10+10+y Combine like terms. y=y+0 Subtract y on both sides. 0y=0 Divide by 0 on each side. y=0 Now plug in what y equals to into what x equals to find the exact value of x. x=4+2/5y x=4+2/5(0) x=4+0 x=4 Your first solution to the data is (4,0).