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write equation in standfrd form
y =mx + b where b = y intercept
5x - 2y =20
5x -20 = 2y
5/2 x -10 = y
when x = 0 y = -10, the y intercept
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Rewrite the equation 5x-2y0 in slope-intercept form?
5x - 2y = 05x - 5x - 2y = 0 - 5x-2y = - 5x(-2y)/-2 = (-5x)/-2y = (5/2)x where the slope is 5/2 and the y-intercept is 0.
Graph the line 5x-10 equals 2y?
2y = 5x - 10Putting into Slope-Intercept form, we have y = 5/2 x - 5. So, the y-intercept is -5 and the slope is 5/2 or 2.5. (x-intercept is 2).
What is the y-intercept of the graph of 2y-5x14?
If you mean 2y = -5x+14 then y = -2.5x+7 whereas -2.5 is the slope and 7 is the y intercept
What is the slope of 5x-2y equals 11?
5x-2y=11 -2y=-5x+11 y=(5/2)x - 11/2 Slope is 5/2
What is the y intercept in this equation 5x-2y equals 20?
5x-2y=20 Subtract 5x on both sides to see what y equals. -2y=20-5x Divide by -2 on each side. y=-10+(5/2)x or y = (5/2)x - 10 (the slope-intercept form of the equation of a line, where the y-intercept is -10) Add 2y to both sides to see what x equals. 5x=20+2y Divide by 5 on each side. x=4+2/5y or x = (2/5)y + 4, where 4 is the x-intercept. (all this work is to show that when the value of y is zero, the line cuts the x-axis at 4) Now plug in what x equals into the equation of what y equals to get the exact value of y. y=-10+5/2x y=-10+5/2(4+2/5y) Distribute the 5/2 to the (4+2/5y) in parentheses. y=-10+10+y Combine like terms. y=y+0 Subtract y on both sides. 0y=0 Divide by 0 on each side. y=0 Now plug in what y equals to into what x equals to find the exact value of x. x=4+2/5y x=4+2/5(0) x=4+0 x=4 Your first solution to the data is (4,0).
What is the x intercept in this equation 5x-2y equals 20?
5x - 2y = 20The x-intercept of a line is the point where its y-value is 0. When y=0, we get 5x = 20, or x=4. This means the coordinates of the x-intercept on this line are (4,0).
What is the x intercept of 5x - 2y 20?
Assuming you meant 5x-2y=20... 5x - 2(0) = 20 5x = 20 x = 4 X-intercept is 4
What is the x and y intercepts for 5x plus 2y equals 20?
The x intercept is the point where y = 0, the y intercept is the point where x =0: For the x intercept: 5x + 2y = 20, but y = 0 => 5x + 0 = 20 => x = 20/5 = 4. So the x intercept is at (4, 0). For the y intercept: 5x + 2y = 20, but x = 0 [The rest of the calculation is left as an exercise for the reader.]
What is 5x-2y equals 10 in slope intercept form?
5x - 2y = 10 2y = 5x - 10 y = 2.5x - 5......which is the equation in slope intercept form.
How do I solve 5x plus 2y equals 20?
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
What is the X intercept of 5X plus 2Y equals 20?
To find the x-intercept, set y equal to zero in the equation 5x + 2y = 20. Then solve for x: 5x + 2(0) = 20. Simplifying, 5x = 20. Dividing both sides by 5, x = 4. Therefore, the x-intercept is (4, 0).
What is the slope intercept form of the equation 5x plus 2y equals 30?
5x+2y = 30 2y = -5x+30 y = -2.5x+15 Therfore the slope is 2.5 and y the intercept is 15.
Find the x-intercept to the following linear equation5x - 2y equals 20?
The x-intercept is found when y=0 Therefore 5x - (2 x 0) = 20 : 5x = 20 : x = 20/5 = 4.
What is the y- intercept and x- intercept for the equation -5x 2y20?
If you mean: -5x+2y = 20 then the x intercept is -4 and the y intercept is 10
Which is a solution to the equation 5x plus 2y equals 9?
If: 5x+2y = 9 Then: y = -2.5x+4.5 in slope intercept form
What is the y-intercept of the line -5x equals 10 - 2y?
(0, 5)
What is the x-intercept for this linear equation 5x-2y equals 20?
5X - 2Y = 20 -2Y = -5X + 20 Y = 5/2X - 10 set to 0 and solve for X 5/2X - 10 = 0 5/2X = 10 X = 4 My TI-84 graphs and confirms this
