Q: How do you write 52 as a product of prime factors?

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2 x 3 x 52

75 expressed as a product of its prime factors is 5 squared, and 3.

4,900 = 22 x 52 x 72

400 = 2 x 2 x 2 x2 x 5 x 5 (or 24 x 52)

The factors of 52 are: 1, 2, 4, 13, 26, 52. The Prime Factors are: 2, 13.

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As a product of its prime factors in exponents: 22*3*52 = 300

225 = 32 x 52

2 x 3 x 52

As a product of its prime factors it is: 2*3*5*5 = 150 or as 2*3*52 = 150

32*52 = 225

2 x 2 x 13 = 52

As a product of its prime factors in exponents: 33*52 = 675

75 expressed as a product of its prime factors is 5 squared, and 3.

To find the HCF of two numbers you first need to write them as the product of their prime factors: 52 = 2x2x13 96 = 2x2x2x2x2x3 The next step is to identify any common prime factors. In this case, both numbers have two 2s as prime factors. Multiply these and you get: 2x2 = 4 Thus the HCF of 52 and 96 is 4.

As a product of its prime factors in exponents: 25*3*52 = 2400 Or as 2.4*103 in scientific notation

As a product of its prime factors in exponents it is: 22*3*52*7 = 2100

As the product of its prime factors in exponents it is: 22*52*17 = 1700