As a product of its prime factors: 2*3*3*5*7 = 630
The prime factorization of 630 is 2 x 3^2 x 5 x 7. This means that 630 can be expressed as the product of these prime numbers raised to their respective exponents. In this case, we have 2 raised to the power of 1, 3 raised to the power of 2, 5 raised to the power of 1, and 7 raised to the power of 1.
2 x 3 x 3 x 5 x 7 = 630
3150
630 315,2 105,3,2 35,3,3,2 7,5,3,3,2
It is: 2*3*3*5*7 = 630
As a product of its prime factors: 2*3*3*5*7 = 630
The prime factorization of 630 is 2 x 3^2 x 5 x 7. This means that 630 can be expressed as the product of these prime numbers raised to their respective exponents. In this case, we have 2 raised to the power of 1, 3 raised to the power of 2, 5 raised to the power of 1, and 7 raised to the power of 1.
As a product of its prime factors: 2*32*5*7 = 630
First you separate it into prime factors (start looking for small factors, such as 2, 3, 5). Then, you combine the factors with exponents.
As a product of its prime factors: 2*3*3*5*7 = 630
2 x 3 x 3 x 5 x 7 = 630
2*3*3*5*7
3150
It is: 630 by finding the prime factors of the given numbers
Add 149, 151, 163 and 167 together.
It is: 630 by multiplying the highest prime factors of both numbers