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It is: 2*3*3*5*7 = 630

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8y ago

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How do you write 630 as a product of prime factors?

It is: 2*3*3*5*7 = 630


What is the prime factorization of 630 using exponents?

The prime factorization of 630 is 2 x 3^2 x 5 x 7. This means that 630 can be expressed as the product of these prime numbers raised to their respective exponents. In this case, we have 2 raised to the power of 1, 3 raised to the power of 2, 5 raised to the power of 1, and 7 raised to the power of 1.


What are 5 numbers multiplied together to get 630?

To find five numbers that multiply to 630, we can start by breaking down 630 into its prime factors: 2 x 3 x 3 x 5 x 7. From this prime factorization, we can see that the five numbers are 2, 3, 3, 5, and 7. So, the five numbers that multiply to 630 are 2, 3, 3, 5, and 7.


What is the prime factorixation of 630 using exponents?

As a product of its prime factors: 2*32*5*7 = 630


How do you write 630 with prime numbers and exponents?

First you separate it into prime factors (start looking for small factors, such as 2, 3, 5). Then, you combine the factors with exponents.


What are all the facors of 630?

As a product of its prime factors: 2*3*3*5*7 = 630


What 5 prime numbers make 630?

2 x 3 x 3 x 5 x 7 = 630


How do you make 630 out of 5 prime numbers?

2*3*3*5*7


What 5 prime numbers multiply together to get 630?

3150


What is the LCM of 42 63 and 105 formula?

It is: 630 by finding the prime factors of the given numbers


How do you make 630 out of 4 prime numbers?

Add 149, 151, 163 and 167 together.


What are prime factors of 630?

The prime factors of 630 are: 2, 3, 5, 7