It is: 2*3*3*5*7 = 630
The prime factorization of 630 is 2 x 3^2 x 5 x 7. This means that 630 can be expressed as the product of these prime numbers raised to their respective exponents. In this case, we have 2 raised to the power of 1, 3 raised to the power of 2, 5 raised to the power of 1, and 7 raised to the power of 1.
To find five numbers that multiply to 630, we can start by breaking down 630 into its prime factors: 2 x 3 x 3 x 5 x 7. From this prime factorization, we can see that the five numbers are 2, 3, 3, 5, and 7. So, the five numbers that multiply to 630 are 2, 3, 3, 5, and 7.
2 x 3 x 3 x 5 x 7 = 630
3150
630 315,2 105,3,2 35,3,3,2 7,5,3,3,2
It is: 2*3*3*5*7 = 630
The prime factorization of 630 is 2 x 3^2 x 5 x 7. This means that 630 can be expressed as the product of these prime numbers raised to their respective exponents. In this case, we have 2 raised to the power of 1, 3 raised to the power of 2, 5 raised to the power of 1, and 7 raised to the power of 1.
To find five numbers that multiply to 630, we can start by breaking down 630 into its prime factors: 2 x 3 x 3 x 5 x 7. From this prime factorization, we can see that the five numbers are 2, 3, 3, 5, and 7. So, the five numbers that multiply to 630 are 2, 3, 3, 5, and 7.
As a product of its prime factors: 2*32*5*7 = 630
First you separate it into prime factors (start looking for small factors, such as 2, 3, 5). Then, you combine the factors with exponents.
As a product of its prime factors: 2*3*3*5*7 = 630
2 x 3 x 3 x 5 x 7 = 630
2*3*3*5*7
3150
Add 149, 151, 163 and 167 together.
It is: 630 by finding the prime factors of the given numbers
To find three numbers that add to 630 and can be represented using multiplication, consider the numbers 210, 210, and 210. While these three numbers add up to 630 (210 + 210 + 210 = 630), their product is (210 \times 210 \times 210). However, if you're looking for a multiplication factor, you could consider (1 \times 1 \times 630) or any variation thereof, where two of the numbers are 1 and the third is 630.